根据四个输入决策做出最终决定 php

Question

我正在使用 CI 框架 PHP，

我想根据四个用户的输入决策做出最终决策结果，

$this->input->post('decision_1', TRUE) == 0 //or 1 or 2 or 3
$this->input->post('decision_2', TRUE) == 0 //or 1 or 2 or 3
$this->input->post('decision_3', TRUE) == 0 //or 1 or 2 or 3
$this->input->post('decision_4', TRUE) == 0 //or 1 or 2 or 3

现在如果任何三个输入相同，那么它将成为最终决策，或者在四个或三个输入中，最大的决策将成为最终决策，

例如，如果决策 1,2,3 为 0，则 final 应为 0 但是如果决策 1,2 是 0，决策 4 是 1，那么 final 也应该是 1。

我尝试使用 switch 语句，但如果所有最少 3 个输入都相同，它确实有效，但如果三个输入不同，则我不起作用，

$result_case = TRUE;
      switch ($result_case) {
      case $this->input->post('decision_1', TRUE) == 1 && $this->input->post('decision_2', TRUE) == 1 && $this->input->post('decision_3', TRUE) == 1 :
          $result = 1;
          break;
      case $this->input->post('decision_1', TRUE) == 1 && $this->input->post('decision_2', TRUE) == 1 && $this->input->post('decision_4', TRUE) == 1 :
          $result = 1;
          break;
      case $this->input->post('decision_1', TRUE) == 1 && $this->input->post('decision_3', TRUE) == 1 && $this->input->post('decision_4', TRUE) == 1:
          $result = 1;
          break;
      case $this->input->post('decision_2', TRUE) == 1 && $this->input->post('decision_3', TRUE) == 1 && $this->input->post('decision_4', TRUE) == 1:
          $result = 1;
          break;
      //
      case $this->input->post('decision_1', TRUE) == 0 && $this->input->post('decision_2', TRUE) == 0 && $this->input->post('decision_3', TRUE) == 0:
          $result = 0;
          break;
      case $this->input->post('decision_1', TRUE) == 0 && $this->input->post('decision_2', TRUE) == 0 && $this->input->post('decision_4', TRUE) == 0:
          $result = 0;
          break;
      case $this->input->post('decision_1', TRUE) == 0 && $this->input->post('decision_3', TRUE) == 0 && $this->input->post('decision_4', TRUE) == 0:
          $result = 0;
          break;
      case $this->input->post('decision_2', TRUE) == 0 && $this->input->post('decision_3', TRUE) == 0 && $this->input->post('decision_4', TRUE) == 0:
          $result = 0;
          break;
      //
      case $this->input->post('decision_1', TRUE) == 2 && $this->input->post('decision_2', TRUE) == 2 && $this->input->post('decision_3', TRUE) == 2:
          $result = 2;
          break;
      case $this->input->post('decision_1', TRUE) == 2 && $this->input->post('decision_2', TRUE) == 2 && $this->input->post('decision_4', TRUE) == 2:
          $result = 2;
          break;
      case $this->input->post('decision_1', TRUE) == 2 && $this->input->post('decision_3', TRUE) == 2 && $this->input->post('decision_4', TRUE) == 2:
          $result = 2;
          break;
      case $this->input->post('decision_2', TRUE) == 2 && $this->input->post('decision_3', TRUE) == 2 && $this->input->post('decision_4', TRUE) == 2:
          $result = 2;
          break;

      default:
          $result = 'Undecided';
  }

是否有任何简单的方法来检查输入决定并做出最终决定？

谢谢，

Answer 1

//save each post in as a key of an array.
$results[$this->input->post('decision_1', TRUE)][] = 1;
...
...
...
//count each type of the post
$results = array_map(function($v){return count($v);}, $results;);
$max = -1;
foreach($results as $k => $v)
{
  if($v >= 3)
    $result = $k;
  $max = $results[$max] > $v ? $max : $k;

}
//if a post type has more or equal to 3, chose it. otherwise chose the biggest key as the result.
$result = isset($result) ? $result : $max;