【发布时间】:2019-07-09 10:02:10
【问题描述】:
我是一个新手,我在将数据传递给我的搜索委托类时遇到问题。问题是我有两个标签,我想在活动标签中搜索。所以我试图发送一个变量来告诉它是哪个选项卡以及要在哪个表中查找值。
我的代码如下所示:
class HomePage extends StatefulWidget {
static final String routeName = 'home';
@override
State<StatefulWidget> createState() {
return new _HomePageState();
}
}
class _HomePageState extends State<HomePage> with TickerProviderStateMixin {
var activeTab = "activity";
var _authToken, _id, _name, _emails, _userImage;
@override
void initState() {
super.initState();
tabController = TabController(vsync: this, length: 2)..addListener(() {
setState(() {
switch (tabController.index) {
case 0:
activeTab = "activity";
break;
case 1:
activeTab = "subparticipants";
break;
}
});
});
}
@override
Widget build(BuildContext context) {
return new Scaffold(
key: _scaffoldKey,
// appBar: new AppBar(
// title: Text('Dashboard'),
// ),
body: DefaultTabController(
length: 2,
child: Scaffold(
appBar: AppBar(
bottom: TabBar(
labelColor: Color(0xFFFFFFFF),
indicatorSize: TabBarIndicatorSize.tab,
tabs: [
//Tab(icon: Icon(Icons.directions_car)),
Tab(
text: "Activity Zone",
),
Tab(
text: "Sub Participant",
)
],
controller: tabController,
),
title: Text(
'Dashboard',
style: new TextStyle(
color: const Color(0xFFFFFFFF),
fontSize: 20.0,
fontWeight: FontWeight.w600,
letterSpacing: 0.3,
),
),
actions: <Widget>[
IconButton(
icon: Icon(Icons.search),
onPressed: () {
showSearch(context: context, delegate: DataSearch(activeTab));
},
)
],
),
body: TabBarView(
controller: tabController,
children: [
TabActivity(),
TabSubparticipant(),
],
),
floatingActionButton: FloatingActionButton(
onPressed: () {
print(
'Current Index: $activeTab');
},
),
drawer: _buildDrawer(context),
),
),
);
}
}
class DataSearch extends SearchDelegate{
final String activeTab;
DataSearch(this.activeTab);
@override
List<Widget> buildActions(BuildContext context){
return [
IconButton(
icon: Icon(Icons.arrow_back),
onPressed: (){
query=activeTab;
},
)
];
}
@override
Widget buildLeading(BuildContext context) => IconButton(
icon: Icon(Icons.close),
onPressed: () => Navigator.of(context).pop(),
);
@override
Widget buildResults(BuildContext context) => Text('Result');
@override
Widget buildSuggestions(BuildContext context) {
return Padding(
padding: const EdgeInsets.all(8.0),
child: Text(
'Search by job id, asset name, client name $query',
style: new TextStyle(
color: Colors.black, fontWeight: FontWeight.bold, fontSize: 22.0),
),
);
}
}
当我尝试获取 $activeTab 并在查询或其他地方显示它时,它只会给出错误:
flutter: The following assertion was thrown building _SearchPage<dynamic>(dirty, dependencies:
flutter: [_LocalizationsScope-[GlobalKey#a02e3], _InheritedTheme], state: _SearchPageState<dynamic>#eceaa):
flutter: 'package:flutter/src/widgets/basic.dart': Failed assertion: line 6173 pos 15: 'child != null': is
我有点困惑我应该如何将价值传递给它。我见过一些类似的问题,但它们没有帮助。喜欢this 或这个question。这些都没有任何这些错误。你能告诉我我做错了什么吗?什么问题?请帮忙。
【问题讨论】:
标签: search flutter dart flutter-dependencies