Python：猜数游戏答案

【问题标题】：Python: Number Guessing GamePython：猜数游戏
【发布时间】：2014-01-28 21:26:33
【问题描述】：

您的程序通过在 1 到 1000（含）范围内随机选择一个整数来选择要猜测的数字。如果玩家的猜测不正确，你的程序应该循环直到玩家最终猜对了数字。你的程序应该不断告诉玩家太高或太低，以帮助玩家“归零”正确答案。游戏结束后，程序应提示用户输入“y”重新玩游戏或“n”退出游戏。

我的问题是每次他们想再次播放时如何生成一个新的随机整数？

这是我的代码。

import random

randomNumber = random.randrange(1, 1000)

def main():
    print ""
    number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
    guess(number)

def guess(number1):
    correct = False
    while not correct:
        if number1 > randomNumber:
            print "Too high. Try again."
            print ""
        elif number1 < randomNumber:
            print "Too low. Try again."
            print ""
        elif number1 == randomNumber:
           break
        number1 = input ("What number do you guess? ")
    if number1 == randomNumber:
       playAagain = raw_input ("Excellent! You guessed the number! Would you like to play again (y or n)? ")
       if playAagain == "y":
            main()

main()

【问题讨论】：

您可能需要考虑不在guess 函数内调用main 函数。这称为递归（因为调用guess 函数的是main 函数）并且可能导致您的程序崩溃。弄清楚如何用循环替换它。

标签： python function

【解决方案1】：

走这条线：

randomNumber = random.randrange(1, 1000)

并将其放入guess:

import random

def main():
    print ""
    number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
    guess(number)

def guess(number1):
    #########################################
    randomNumber = random.randrange(1, 1000)
    #########################################
    correct = False
    while not correct:
        if number1 > randomNumber:
            print "Too high. Try again."
            print ""
        elif number1 < randomNumber:
            print "Too low. Try again."
            print ""
        elif number1 == randomNumber:
           break
        number1 = input ("What number do you guess? ")
    if number1 == randomNumber:
       playAagain = raw_input ("Excellent! You guessed the number! Would you like to play again (y or n)? ")
       if playAagain == "y":
            main()

main()

现在，每次调用函数时都会创建一个新的随机整数。

【讨论】：

【解决方案2】：

在main()中放一个循环，在循环的开头初始化randomNumber。

【讨论】：

【解决方案3】：

请尝试删除从随机到while循环开始的四个空格

import random

print " welcome to game of guessing "
print "you have 6 attempts"
num1 = random.randint(1,100)
print num1  # this is your computer generated number ( skip while running :only for test purpose)
num2 = num1+random.randint(1,15)
print " hint: number is close to " + str(num2)

count=1

而计数

elif inputnum<str(num1):
    print " number is lower than correct one "
    count=count+1
elif inputnum>str(num1):
    print "number is greater than correct one"
    count=count+1
else:
    break

【讨论】：

【解决方案4】：

你只需要像这样定义你的 main() 函数。

def main():

    global randomNumber
    print ""
    randomNumber = random.randrange(1, 1000)
    number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
    guess(number)

一切都会完美。希望这会有所帮助。

【讨论】：