【问题标题】:LINQ Distinct not using the IEqualityComparer? [duplicate]LINQ Distinct 不使用 IEqualityComparer? [复制]
【发布时间】:2015-06-25 14:13:51
【问题描述】:

我有以下型号:

public class Word {
      public string Original { get; set; }
      public string Normalized { get; set; }
      public string Root { get; set; }
      public string Subroot { get; set; }
      public Regex SubrootRegex { get; set; }
}

我创建了以下三个IEqualityComparer<Word>:

public class NormalizedWordComparer : IEqualityComparer<Word> {
     public bool Equals(Word x, Word y) {
          return x.Normalized == y.Normalized;
     }
     public int GetHashCode(Word obj) {
          return obj.GetHashCode();
     }
}

public class RootWordComparer : IEqualityComparer<Word> {
     public bool Equals(Word x, Word y) {
          return x.Root == y.Root;
     }
     public int GetHashCode(Word obj) {
          return obj.GetHashCode();
     }
}

public class SubrootWordComparer : IEqualityComparer<Word> {
     public bool Equals(Word x, Word y) {
          return x.Subroot == y.Subroot;
     }
     public int GetHashCode(Word obj) {
          return obj.GetHashCode();
     }
}

在另一堂课中,我正在尝试执行以下操作:

_normalizedWords = ConfigurationFacade.Words.Select(w => {
     Word word = new Word() { Original = w };
     word.Normalized = Normalize(word, _filters);
     word.Root = GetRoot(word.Normalized, ConfigurationFacade.WordRootPercentage);
     word.Subroot = GetRoot(word.Root, ConfigurationFacade.WordSubrootPercentage);
     word.SubrootRegex = null; //Complicated regex here
     return word;
}).Distinct(new NormalizedWordComparer());

_wordRoots = _normalizedWords.Distinct(new RootWordComparer());
_wordSubroots = _wordRoots.Distinct(new SubrootWordComparer());

但是,_normalizedWords、_wordRoots 和 _wordSubroots 都以相同数量的元素结束,就好像 Distinct() 方法不起作用或比较器被忽略了一样。

我用调试器检查了元素,有很多有相同的Root值,所以_wordRoots中应该只有一个,但事实并非如此,它们没有被删除或过滤.

为什么我的Distinct() 不起作用?

【问题讨论】:

  • @TimSchmelter 有一点错别字。我的错!

标签: c# .net linq ienumerable


【解决方案1】:

为什么我的 Distinct() 不起作用?

因为Distinct首先检查哈希码(因为这是一个快速检查两个对象可能是否相等)和然后致电Equals。由于您的 GetHashCode 实现都是相同的(并且不对应于您的 Equals 方法),因此 Distinct 无法按您的预期工作。

更改您的GetHashCode 方法以对应Equals:

public class NormalizedWordComparer : IEqualityComparer<Word> {
     public bool Equals(Word x, Word y) {
          return x.Normalized == y.Normalized;
     }
     public int GetHashCode(Word obj) {
          return obj.Normalized.GetHashCode();
     }
}

public class RootWordComparer: IEqualityComparer<Word> {
     public bool Equals(Word x, Word y) {
          return x.Root == y.Root;
     }
     public int GetHashCode(Word obj) {
          return obj.Root.GetHashCode();
     }
}

public class SubrootWordComparer : IEqualityComparer<Word> {
     public bool Equals(Word x, Word y) {
          return x.Subroot == y.Subroot;
     }
     public int GetHashCode(Word obj) {
          return obj.Subroot.GetHashCode();
     }
}

【讨论】:

  • 我明白了!既然你为我澄清了,这一切都说得通了!谢谢!
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