【发布时间】:2020-08-30 05:41:56
【问题描述】:
我正在编写一个测试程序,其方式类似于出租商店的库存跟踪器。 我正在检查用户输入的数据,但我的一个 if 语句检查条目时经常收到 ValueError。
def check_entries (): #This function checks whether what the user entered is correct for the entry and store
global customer_name_error_label
global receipt_numb_error_label
global item_hired_name_error_label
global numb_items_hired_error_label
global numb_items_hired_numb_rel_error_label
if customer_name_entry.get () .isalpha () and receipt_number_entry.get().isdigit() and item_hired_entry.get () .isalpha ():
if number_of_items_hired_entry.get () .isdigit () and int (number_of_items_hired_entry.get () ) >0 and int (number_of_items_hired_entry.get () ) <500:
customer_name_error_label.grid_forget ()
receipt_numb_error_label.grid_forget ()
item_hired_name_error_label.grid_forget ()
numb_items_hired_error_label.grid_forget ()
numb_items_hired_numb_rel_error_label.grid_forget ()
append_lists ()
else:
if customer_name_entry.get () .isalpha () ==False:
customer_name_error_label=Label (main_frame,text="Please enter a name that only has letters,no numbers ,and there must be a name entered ",bg='red')
customer_name_error_label.grid (row=0,column=3)
if receipt_number_entry.get () .isdigit() ==False:
receipt_numb_error_label=Label (main_frame,text="Please enter a receipt number that is only a number and doesn't have any letters or symbols.",bg='red')
receipt_numb_error_label.grid(row=1,column=3)
if item_hired_entry.get () .isalpha ()== False:
item_hired_name_error_label=Label (main_frame,text="Please enter a item name that only has letters,numbers and symbols aren't accepted.",bg='red')
item_hired_name_error_label.grid (row=2,column=3)
if number_of_items_hired_entry.get ().isdigit ()== False:
numb_items_hired_error_label=Label (main_frame,text="The number of items hired can only be a number,symbols,and letters aren't accepted.",bg='red')
numb_items_hired_error_label.grid (row=4,column=3)
if int (number_of_items_hired_entry.get () ) <0 and int (number_of_items_hired_entry.get () ) >500:
numb_items_hired_numb_rel_error_label=Label (main_frame,text="The number of items hired can only be more then 0 and less then 500",bg='red')
numb_items_hired_numb_rel_error_label.grid (row=5,column=2)
有一张我正在输入的图像,它是所有条目的空字符串,然后我按下附加详细信息按钮。]
这是错误 if int (number_of_items_hired_entry.get () ) <0 and int (number_of_items_hired_entry.get () ) >500: ValueError: invalid literal for int() with base 10: ''
【问题讨论】:
-
修正缩进。你觉得空字符串怎么能转成整数,不要对比
False用not,用if not (0 < number < 500): -
你期待
int('')的结果是什么?
标签: python python-3.x tkinter python-3.7