链接 libcrypto.dylib 时出现链接器错误答案

【问题标题】：linker error when linking libcrypto.dylib链接 libcrypto.dylib 时出现链接器错误
【发布时间】：2020-12-28 11:15:08
【问题描述】：

macOS 10.14.3、Xcode 9.4.1：

我正在尝试在我的项目中使用podofo。我收到以下错误：

ld: warning: ignoring file /usr/local/lib/libcrypto.dylib, file was built for unsupported file format ( 0x62 0x6F 0x6F 0x6B 0x00 0x00 0x00 0x00 0x6D 0x61 0x72 0x6B 0x00 0x00 0x00 0x00 ) which is not the architecture being linked (x86_64): /usr/local/lib/libcrypto.dylib
ld: warning: ignoring file /usr/local/lib/libcrypto.dylib, file was built for unsupported file format ( 0x62 0x6F 0x6F 0x6B 0x00 0x00 0x00 0x00 0x6D 0x61 0x72 0x6B 0x00 0x00 0x00 0x00 ) which is not the architecture being linked (x86_64): /usr/local/lib/libcrypto.dylib
Undefined symbols for architecture x86_64:
  "_EVP_CIPHER_CTX_free", referenced from:
      PoDoFo::RC4CryptoEngine::~RC4CryptoEngine() in libpodofo.a(PdfEncrypt.o)
      PoDoFo::AESCryptoEngine::~AESCryptoEngine() in libpodofo.a(PdfEncrypt.o)
  "_EVP_CIPHER_CTX_new", referenced from:
      PoDoFo::RC4CryptoEngine::RC4CryptoEngine() in libpodofo.a(PdfEncrypt.o)
      PoDoFo::AESCryptoEngine::AESCryptoEngine() in libpodofo.a(PdfEncrypt.o)

我做错了什么？这是什么意思？

非常感谢您的宝贵时间。

【问题讨论】：

标签： macos openssl libcrypto

【解决方案1】：

0x62 0x6F 0x6F 0x6B 0x00 0x00 0x00 0x00 0x6D 0x61 0x72 0x6B 0x00 0x00 0x00 0x00

Ascii 是BOOK MARK 。

这里的/usr/local/lib/libcrypto.dylib实际上是你要在程序中链接的库吗？

【讨论】：

'/usr/local/lib/libcrypto.dylib' 是一个软链接。该库是'/usr/local/Cellar/openssl@1.1/1.1.1i/lib/libcrypto.lib'。
我把它复制到 /usr/local/lib.成功了！非常感谢。