如果用户没有在python3中提供语音输入，如何手动获取用户输入答案

【问题标题】：How to manually take user input if user doesn't give voice input in python3如果用户没有在python3中提供语音输入，如何手动获取用户输入
【发布时间】：2020-02-05 18:58:00
【问题描述】：

我正在使用 Python3 的 pyttsx3 和 speech_recognition 包来获取用户的语音输入。但是如果用户没有给出任何语音输入，超时后用户必须手动输入怎么办？请帮我解决这个问题！

import pyttsx3
import speech_recognition as sr
import pyjokes

engine = pyttsx3.init('sapi5')
voices = engine.getProperty('voices')
r = sr.Recognizer()
user_jokes = "Set a range in number..."
print(user_jokes)
engine.say(user_jokes)
engine.runAndWait()
with sr.Microphone() as source:
    user_jokes_rec = r.listen(source, timeout = 2)
user_jokes_X = r.recognize_google(user_jokes_rec, language='en-US')
if user_jokes_X is None:
    user_jokes_X = int(input("Set a range for jokes... "))
for x in range(user_jokes_X):
    user_jo = pyjokes.get_joke()
    print(user_jo)
    engine.say(user_jo)
    engine.runAndWait()

在这段代码中，if条件应该满足，user_jokes_X的值为空或无，用户手动输入范围？

【问题讨论】：

标签： python python-3.x voice-recognition

【解决方案1】：

您可以像这样将程序扔到 try 块中：

import pyttsx3
import speech_recognition as sr
import pyjokes

engine = pyttsx3.init()
voices = engine.getProperty('voices')
r = sr.Recognizer()
user_jokes = "Set a range in number..."
print(user_jokes)
engine.say(user_jokes)
engine.runAndWait()
try:
    with sr.Microphone() as source:
        user_jokes_rec = r.listen(source, timeout = 2)
        user_jokes_X = r.recognize_google(user_jokes_rec, language='en-US')
except:
    user_jokes_X = int(input("Set a range for jokes... "))
for x in range(user_jokes_X):
    user_jo = pyjokes.get_joke()
    print(user_jo)
    engine.say(user_jo)
    engine.runAndWait()

如果这能解决您的问题，请告诉我。

【讨论】：

【解决方案2】：

您可以这样尝试：except sr.UnknownValueError as e 在下面显示的异常中，因为它会由于没有语音输入而引发 UnknownValueError：

try:
    with sr.Microphone() as source:
    user_jokes_rec = r.listen(source)
    user_jokes_X = r.recognize_google(user_jokes_rec, language='en-US')
except sr.UnknownValueError as e:
    user_jokes_X = int(input("Set a range for jokes... "))

【讨论】：