如何使用语音识别来获取用户的语音输入？答案

【问题标题】：How to use speech recognition to get voice input from user?如何使用语音识别来获取用户的语音输入？
【发布时间】：2022-08-02 19:19:33
【问题描述】：

enter code here

sr = s.Recognizer()
print(\'\'\' listening...
speak the first card\'\'\')

with s.Microphone() as m:
    audio = sr.listen(m)
    query = sr.recognize_google(audio, language=\'eng-in\')

first_card = input(\"Enter the first card: \")
second_card = input(\"Enter the second card: \")
third_card = input(\"Enter the third card: \")
fourth_card = input(\"Enter the fourth card: \")
print(\"the upnext cards are\", fourth_card, third_card, second_card, first_card)

我希望用户语音输入第一张卡，第二张卡等等，而不是用键盘输入它们。

标签： python input speech-recognition

【解决方案1】：

如果您将以下内容放在一个while循环中（完整代码请参见答案的末尾），您可以通过将每次附加到列表中来获得所需次数的用户语音输入。

with s.Microphone() as m:
    audio = sr.listen(m)
    query = sr.recognize_google(audio)
    cards.append(query) #where cards is the list of user inputted cards

请注意，有时会出现无法识别的输入，这就是为什么下面的示例使用一个计数器，当我们成功识别语音输入时会递增（如果我们到达“尝试”部分的末尾，我们知道输入已经认可）。

显然，有时这不会准确识别语音输入，您可以向用户展示什么是“查询”并让他们确认这是正确的/允许他们重试（尽管在我的测试中语音输入一直非常准确） .

import speech_recognition as s

cards = []
numberOfCards = 4

validInputs = 0

while validInputs < numberOfCards: 
    sr = s.Recognizer()
    with s.Microphone() as m:
        print("Speak for card", (validInputs + 1), ":")
        audio = sr.listen(m)

    try:
        query = sr.recognize_google(audio)
        print("card", (calidInputs + 1), ":", query)
        cards.append(query)
        validInputs += 1
    except s.UnknownValueError:
        print("unknown input, please try again")
    except s.RequestError as e:
        print("couldn't get results from Google Speech Recognition service; {0}".format(e))

print("the upnext cards are", cards[3], cards[2], cards[1], cards[0])

运行它将输出：

Speak for card 1:
card 1: red
Speak for card 2:
card 2: green
Speak for card 3:
card 3: blue
Speak for card 4:
card 4: yellow
the upnext cards are yellow blue green red
>>>

我相信这就是您想要实现的目标:)

【讨论】：