我想输入作为开始输入，例如22Ef 和FFFF 作为结束输入，我想打印这两个输入之间的所有字符串，输出应该是这样的
22Ef
22EA
22EB
.
.
.
FFFE
FFFF
这是我要选择的字符串
0123456789abcdefABCDEF
【问题讨论】：
此解决方案避免遍历从 0000 到您的起始输入的所有组合：
start = '22Ef'
end = 'FFFF'
characterset = '0123456789abcdefABCDEF'
base = len(characterset)
baseNnumber = [] # little endian list of integers each representing a digit
# find base N representation of start
exponent = 0
startval = 0
for i in start[::-1]:
digit = characterset.index(i)
baseNnumber.append(digit)
startval += digit * base**exponent
exponent += 1
baseNnumber.extend([0]*(len(end)-len(start)))
# find representation of end
exponent = 0
endval = 0
for i in end[::-1]:
digit = characterset.index(i)
endval += digit * base**exponent
exponent += 1
# number of times to print
increments = endval - startval + 1
for i in range(increments):
index = 0
outstr = ''
# remove leading zeros
notzero = False
for i in baseNnumber[::-1]:
notzero = notzero | (i != 0)
# add new character to string
outstr += characterset[i] * notzero
# the actual printing
print(outstr)
# increment baseNnumber by 1
while True:
baseNnumber[index] += 1
if baseNnumber[index] == base:
baseNnumber[index] = 0
index += 1
else:
break
如果您希望包含前导零，您可能希望将第 34-38 行替换为 notzero 旨在删除它们：
for i in baseNnumber[::-1]:
outstr += characterset[i]
或者，如果您确定开始和结束输入相同，只需删除第 17 行并在上面进行替换，因为它旨在解决开始和结束输入长度不同的问题。
【讨论】：
以下（使用来自itertools 的product 函数）应该可以工作：
from itertools import product
strings = []
start = "22Ef"
end = "FFFF"
include = False
for i in product("0123456789abcdefABCDEF", repeat=4):
curstring = "".join(i)
if curstring == start:
include = True
if curstring == end:
strings.append(curstring)
break
if include:
strings.append(curstring)
print(strings)
【讨论】：