我不确定您想要什么,因为在标题中您要求有序边,但在您的示例中,您要求边中的有序节点。在我的示例中,我展示了两者的排序。请注意,我使用列表推导来创建新的边列表——原始的边列表 (some_edges) 没有改变。
首先如何对边列表中的单个节点元组进行排序。也就是说,边的顺序相同,但其中的节点是排序的。
import networkx as nx
g = nx.Graph()
g.add_edges_from([
(5, 2),
(2, 1),
(3, 2),
(4, 2)
])
some_edges = g.edges(2)
print("Not sorted: ", some_edges)
print("SORTED")
# sort nodes in edges
some_edges_1 = [tuple(sorted(edge)) for edge in some_edges]
print("Sorted nodes:", some_edges_1)
现在如何对边列表中的边进行排序。
# sort edges in list of edges
some_edges_2 = sorted(some_edges_1)
print("Sorted edges:", some_edges_2)
上面两个代码块的输出:
Not sorted: [(2, 1), (2, 3), (2, 4), (2, 5)]
SORTED
Sorted nodes: [(1, 2), (2, 3), (2, 4), (2, 5)]
Sorted edges: [(1, 2), (2, 3), (2, 4), (2, 5)]
这里还有一个反向排序的示例,您可以实际看到排序单个边和排序边列表之间的区别。
print("Not sorted: ", some_edges)
print("SORTED REVERSE")
# sort nodes in edges
some_edges_1 = [tuple(sorted(edge, reverse=True)) for edge in some_edges]
print("Sorted nodes:", some_edges_1)
# sort edges in list of edges
some_edges_2 = sorted(some_edges_1, reverse=True)
print("Sorted edges:", some_edges_2)
输出:
Not sorted: [(2, 1), (2, 3), (2, 4), (2, 5)]
SORTED REVERSE
Sorted nodes: [(2, 1), (3, 2), (4, 2), (5, 2)]
Sorted edges: [(5, 2), (4, 2), (3, 2), (2, 1)]