如何与 R 包 sf 进行“完整”联合

Question

我尝试使用sf::st_union 在三个多边形之间进行联合。在下图中显示了 ArcGIS "Overlay, Union, All" 的结果，我希望通过使用 R 中的 sf 包获得与 'OUTPUT' 中的五个不同多边形相似的结果。

library(sf)
a1 <- st_polygon(list(rbind(c(0, 10), c(45, 10), c(45, 90), c(0, 90), c(0, 10))))
a2 <- st_polygon(list(rbind(c(45, 10), c(90,10), c(90, 90), c(45, 90), c(45, 10))))
b <- st_polygon(list(rbind(c(15, 5), c(75, 5), c(75, 50), c(15, 50), c(15, 5))))
a <- st_sf(c(st_sfc(a1), st_sfc(a2)))
b <- st_sf(st_sfc(b))
a$station <- c(1, 2)
b$type <- "A"
ab_union <- st_union(a, b)

在这个简单的示例中，生成的 sf 对象“ab_union”将只包含两个多边形，而不是预期的五个。我可以通过使用sf包中的函数得到上图五个对象的想要的结果吗？

Answer 1

我没有找到可以一步完成所有事情的功能，但这是解决您的问题的一种方法：

library(sf)
#> Linking to GEOS 3.6.1, GDAL 2.2.3, PROJ 4.9.3
library(tidyverse)

a1 <- st_polygon(list(rbind(c(0, 10), c(45, 10), c(45, 90), c(0, 90), c(0, 10))))
a2 <- st_polygon(list(rbind(c(45, 10), c(90,10), c(90, 90), c(45, 90), c(45, 10))))
b1 <- st_polygon(list(rbind(c(15, 5), c(75, 5), c(75, 50), c(15, 50), c(15, 5))))

a <- st_sf(station=c(1, 2), geometry=st_sfc(a1, a2))
b <- st_sf(type="A",   geometry=st_sfc(b1))

st_agr(a) = "constant" #to avoid warnings, but see https://github.com/r-spatial/sf/issues/406
st_agr(b) = "constant"

#Operations
plot(st_geometry(st_union(a,b)))

op1 <- st_difference(a,st_union(b)) #notice the use of st_union()
plot(st_geometry(op1), border="red", add=TRUE)

op2 <- st_difference(b, st_union(a)) #notice the order of b and a and st_union()
plot(st_geometry(op2), border="green", add=TRUE)

op3 <- st_intersection(b, a) #notice the order of b and a
plot(st_geometry(op3), border="blue", add=TRUE)

union <- rbind(op1, op2, op3) #Error because op1 (op2) doesn't have the column "type" ("station")
#> Error in match.names(clabs, names(xi)): names do not match previous names

op11 <- dplyr::mutate(op1, type=NA)
op22 <- dplyr::mutate(op2, station=NA)

union <- rbind(op11, op22, op3)
(as.data.frame(union)) #The row names must be ordered.
#>     station type                       geometry
#> 1         1 <NA> POLYGON ((15 10, 0 10, 0 90...
#> 2         2 <NA> POLYGON ((45 50, 45 90, 90 ...
#> 3        NA    A POLYGON ((75 10, 75 5, 15 5...
#> 11        1    A POLYGON ((15 10, 15 50, 45 ...
#> 1.1       2    A POLYGON ((45 50, 75 50, 75 ...
plot(union)


#Other approach for avoid create the new columns would be:

union2 <- dplyr::bind_rows(op1, op2, op3) #But see discusion here: https://github.com/r-spatial/sf/issues/49
#> Warning in bind_rows_(x, .id): Vectorizing 'sfc_POLYGON' elements may not
#> preserve their attributes

#> Warning in bind_rows_(x, .id): Vectorizing 'sfc_POLYGON' elements may not
#> preserve their attributes

#> Warning in bind_rows_(x, .id): Vectorizing 'sfc_POLYGON' elements may not
#> preserve their attributes

^{由reprex package (v0.2.1) 于 2019 年 4 月 6 日创建}

我参考的讨论：
https://github.com/r-spatial/sf/issues/406

https://github.com/r-spatial/sf/issues/49

Answer 2

我也需要这样的功能，所以这是我的任意 sf 对象版本，避免显式添加缺失的列。它还需要“plyr”库（函数 rbind.fill）：

my_union <- function(a,b) {
   #
   # function doing a real GIS union operation such as in QGIS or ArcGIS
   #
   # a - the first sf
   # b - the second sf
   #
   st_agr(a) = "constant"
   st_agr(b) = "constant"
   op1 <- st_difference(a,st_union(b))
   op2 <- st_difference(b, st_union(a))
   op3 <- st_intersection(b, a)
   union <- rbind.fill(op1, op2, op3)
   return(st_as_sf(union))
}