使用 pynput 进行键盘按下检测

Question

from pynput import keyboard 

def on_press(key): 
    print('Key %s pressed' % key) 

def on_release(key): 
    print('Key %s released' %key) 

with keyboard.Listener( on_press=on_press, on_release=on_release) as listener: 
    listener.join()

如果我一直按住 F1 按钮并松开， 它说

Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 released

如果我一直按 F1 按钮并松开，我希望它像下面那样工作

Key Key.f1 pressed
Key Key.f1 released

请帮帮我:)

Answer 1

pressed = False

def on_press(key): 
    global pressed
    if not pressed and key == keyboard.Key.f1: # only if key is not held
        print('Key %s pressed' % key) 
        pressed = True # key is held

def on_release(key):
    global pressed 
    if key == keyboard.Key.f1:
        print('Key %s released' %key) 
        pressed = False # key is released

代码很容易解释，你只需提供一个布尔值pressed，当你按下F1键时，它是True，当你释放它时，它是False。如果press 是False，您只需忽略on_press“信号”。

如果您想用每个键实现这一点，您必须将每个键的状态存储在字典中（或作为类似对象）。

pressed = {}

def on_press(key): 
    if key not in pressed: # Key was never pressed before
        pressed[key] = False
    
    if not pressed[key]: # Same logic
        pressed[key] = True
        print('Key %s pressed' % key) 

def on_release(key):  # Same logic
    pressed[key] = False
    print('Key %s released' %key)