【问题标题】:Python + Pandas + Data visualization : How to get percentages for each row and visualize categorical data?Python + Pandas + 数据可视化:如何获取每行的百分比并可视化分类数据?
【发布时间】:2018-11-01 19:24:29
【问题描述】:

我正在对贷款预测数据集(Pandas 数据框)进行探索性数据分析。此数据框有两列:Property_Area,其值为三种类型 - Rural、Urban、Semiurban。另一列是 Loan_Status 明智值有两种类型 - Y、N。我想绘制这样的图表:沿 X 轴应该有 Property_Area,并且,对于每种类型的 3 个区域,我想显示接受的贷款百分比或沿 Y 轴拒绝。该怎么做?

这是我的数据示例:

data = pd.DataFrame({'Loan_Status':['N','Y','Y','Y','Y','N','N','Y','N','Y','N'], 
       'Property_Area': ['Rural', 'Urban','Urban','Urban','Urban','Urban',
       'Semiurban','Urban','Semiurban','Rural','Semiurban']})

我试过这个:

status = data['Loan_Status']
index = data['Property_Area']
df = pd.DataFrame({'Loan Status' : status}, index=index)
ax = df.plot.bar(rot=0)

data is the dataframe for the original dataset

输出:

编辑: 我能够做我想做的事,但为此我不得不写一段很长的代码:

new_data = data[['Property_Area', 'Loan_Status']].copy()
count_rural_y = new_data[(new_data.Property_Area == 'Rural') & (data.Loan_Status == 'Y') ].count()
count_rural = new_data[(new_data.Property_Area == 'Rural')].count()
#print(count_rural[0])
#print(count_rural_y[0])
rural_y_percent = (count_rural_y[0]/count_rural[0])*100
#print(rural_y_percent)

#print("-"*50)

count_urban_y = new_data[(new_data.Property_Area == 'Urban') & (data.Loan_Status == 'Y') ].count()
count_urban = new_data[(new_data.Property_Area == 'Urban')].count()
#print(count_urban[0])
#print(count_urban_y[0])
urban_y_percent = (count_urban_y[0]/count_urban[0])*100
#print(urban_y_percent)

#print("-"*50)

count_semiurban_y = new_data[(new_data.Property_Area == 'Semiurban') & (data.Loan_Status == 'Y') ].count()
count_semiurban = new_data[(new_data.Property_Area == 'Semiurban')].count()
#print(count_semiurban[0])
#print(count_semiurban_y[0])
semiurban_y_percent = (count_semiurban_y[0]/count_semiurban[0])*100
#print(semiurban_y_percent)

#print("-"*50)

objects = ('Rural', 'Urban', 'Semiurban')
y_pos = np.arange(len(objects))
performance = [rural_y_percent,urban_y_percent,semiurban_y_percent]
plt.bar(y_pos, performance, align='center', alpha=0.5)
plt.xticks(y_pos, objects)
plt.ylabel('Loan Approval Percentage')
plt.title('Area Wise Loan Approval Percentage')

plt.show()

输出:

如果可能的话,您能否建议我一个更简单的方法?

【问题讨论】:

  • 当您说“它不起作用”时,您是什么意思?错误?看起来不像你想要的?请给我们多一点继续。您能否提供一些样本或虚拟数据以及您目前绘制的图片?
  • 已编辑。请看。
  • 您能否提供一些示例数据。正如@G.Anderson 也指出的那样,给定的信息不足以重现该问题。
  • 感谢您添加示例数据。我会首先将数据作为多列引入,然后执行 `groupby('Property_Area').count()' 来获取您的实际值计数,然后尝试绘制
  • 关于您的编辑,我很高兴您能够解决它。这个答案Pandas percentage of total with groupby 提供了一个基于总数百分比创建聚合列的快速概述。这可能会给你更简单的代码。

标签: python pandas matplotlib data-visualization crosstab


【解决方案1】:

Pandas Crosstabsnormalize 会让这一切变得简单

在 pandas 数据框中获取 2+ 列并获取 每一行 百分比的简单方法是使用 pandas crosstab 函数和 normalize = 'index'


交叉表函数的查找方式如下:

# Crosstab with "normalize = 'index'". 
df_percent = pd.crosstab(data.Property_Area,data.Loan_Status,
                         normalize = 'index').rename_axis(None)

# Multiply all percentages by 100 for graphing. 
df_percent *= 100

这将输出df_percent,如下所示:

Loan_Status          N          Y
Rural        50.000000  50.000000
Semiurban    66.666667  33.333333
Urban        16.666667  83.333333

然后您可以非常轻松地将其绘制到您的条形图中:

# Plot only approvals as bar graph. 
plt.bar(df_percent.index, df_percent.Y, align='center', alpha=0.5)
plt.ylabel('Loan Approval Percentage')
plt.title('Area Wise Loan Approval Percentage')

plt.show()

并得到结果图表:

Here you can see the code working in google colab


这是我为此答案生成的示例数据框:

data = pd.DataFrame({'Loan_Status':['N','Y','Y','Y','Y','N','N','Y','N','Y','Y'
   ], 'Property_Area': ['Rural', 'Urban','Urban','Urban','Urban','Urban',
   'Semiurban','Urban','Semiurban','Rural','Semiurban']})

创建此示例数据框:

   Loan_Status Property_Area
0            N         Rural
1            Y         Urban
2            Y         Urban
3            Y         Urban
4            Y         Urban
5            N         Urban
6            N     Semiurban
7            Y         Urban
8            N     Semiurban
9            Y         Rural
10           Y     Semiurban

【讨论】:

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