【发布时间】:2017-05-09 02:05:49
【问题描述】:
如何使用 Hibernate 验证器来验证构造函数或方法中的参数?我希望在创建 ValueObject 之前进行验证,因此我可以抛出异常而不创建对象,除非所有参数都有效。
如果可能的话,基本上我会尝试使用注释而不是这样做:
public class ConditionalPerson {
private String name;
private String surname;
private int age;
public ConditionalPerson(String name, String surname, int age){
if (name == null || surname == null || age < 1) {
throw new IllegalArgumentException();
}
this.name = name;
this.surname = surname;
this.age = age;
}
}
我尝试过像这样关注docs,这似乎可行,但仍会导致对象被创建。
public class Person {
@NotNull(message = "Name can't be null")
@NotEmpty(message = "Name can't be empty")
@Length(min=1)
private String name;
@NotNull(message = "Surname can't be null")
@NotEmpty(message = "Surname can't be empty")
@Length(min=1)
private String surname;
@Range(min=100, max=200)
private int age;
public Person(String name, String surname, int age){
this.name = name;
this.surname = surname;
this.age = age;
}
}
给构造函数参数加注解好像没有效果
public Person(@NotNull String name,
@NotNull String surname,
@Range(min=100, max=200) int age) {
...
}
我是如何创建对象的:
public class Example {
Person person;
ConditionalPerson person2;
public static void main(String[] args) {
Example example = new Example();
example.makePerson();
example.makeConditionalPerson();
}
public void makePerson() {
person = new Person(null, "", 12);
Validator validator = ValidatorSingleton.getValidator();
Set<ConstraintViolation<Person>> violations = validator.validate(person);
if (violations.size() > 0) {
throw new IllegalArgumentException();
}
}
public void makeConditionalPerson() {
person2 = new ConditionalPerson(null, "", 123);
}
}
验证器:
public class ValidatorSingleton {
private static final ValidatorFactory factory = Validation.buildDefaultValidatorFactory();
private static final javax.validation.Validator validator = factory.getValidator();
private ValidatorSingleton(){}
public static Validator getValidator() {
return validator;
}
}
【问题讨论】:
标签: java aspectj bean-validation hibernate-validator oval