如何从表的单列中获取 2 个子字符串作为 2 列

Question

[{"key":"Mobile","value":"9100617634"},{"key":"Email","value":"balajirao1@ziaff.in"}]

上面的一个代表一个表的一列中的值。 我想要 2 个名为 mobile 和 email 的列，它们的值分别为 9000617634,balajirao@ziraff。 如何进入sql server。

见下图。

mobile             Email
------             ------------
9100617634         balajirao1@ziaff.in

Answer 1

你可以使用 Pivot 函数将行值转换为列， 下面是实现的静态代码

SELECT * FROM(
   SELECT
     columns_name
   FROM
      table_name
     ) M
   PIVOT (MAX(Key) FOR table_name IN (mobile ,Email))AS  P ;

Answer 2

嗯，辛苦地做这件事很有趣:)

--initial string
declare @s1 varchar(1000) = (select '[{"key":"Mobile","value":"9100617634"},{"key":"Email","value":"balajirao1@ziaff.in"}]')

--selecting first part and second part of string
declare @mobile varchar(100) = (select right(left(@s1,charindex('}',@s1)-1),len(left(@s1,charindex('}',@s1))) - charindex(':',left(@s1,charindex('}',@s1)))-1))
declare @mail varchar(100) = (select right(@s1,charindex(':',reverse(@s1))-1))

--getting rid of extra characters
set @mobile = (right(@mobile, len(@mobile) - charindex(':',@mobile)))
set @mail = (left(@mail, len(@mail) - charindex('}',reverse(@mail))))


--getting rid of double quotes
set @mobile = replace(@mobile,'"','')
set @mail = replace(@mail,'"','')

--selecting data
select 
@mobile as Mobile,
@mail as Mail

结果如下：

手机邮件

9100617634 balajirao1@ziaff.in

Answer 3

选择 当 [MOBILE/PHONE] 像 '[a-z]%' 然后为 null 否则 [MOBILE/PHONE] 以 [MOBILE/PHONE] 结尾时， ISNUMERIC(email)=0 然后 EMAIL 以 EMAIL 结尾的情况 从 ( 选择 REPLACE(SUBSTRING(RIGHT(right(left(AC.Communication,charindex('}',AC.Communication)),len(left(AC.Communication,charindex('}',AC.Communication))) - charindex(' :',left(AC.Communication,charindex('}',AC.Communication)))),LEN(right(left(AC.Communication,charindex('}',AC.Communication)),len(left(AC .Communication,charindex('}',AC.Communication))) - charindex(':',left(AC.Communication,charindex('}',AC.Communication)))))-CHARINDEX(':',right (left(AC.Communication,charindex('}',AC.Communication)),len(left(AC.Communication,charindex('}',AC.Communication))) - charindex(':',left(AC.Communication) Communication,charindex('}',AC.Communication)))))),2,CHARINDEX(']',AC.Communication)),'"}','') AS [手机/电话], 替换(替换(左(右(AC.Communication,charindex(':',reverse(AC.Communication))),LEN(右(AC.Communication,charindex(':',reverse(AC.Communication))))) -charindex('}',reverse(right(AC.Communication,charindex(':',reverse(AC.Communication)))))),':"',''),'"','') AS电子邮件

来自 DimAccountContact 作为 AC