使用PHP将动态html表中的多行插入到MYsql

Question

情景

我有一张计分卡，它是从 MTSQL 中的另一个表填充的，其中包含未知数量的玩家。每周需要对球员进行评分，并且这些分数需要输入到 mySQL。

为 Mysql 表调用成员创建的动态 html 表。

 <form method="post" action="scores-add" id="member-add-form"  enctype="multipart/form-data">
  <div class="table-responsive">
   <table id="data-table-1" class="table table-striped table-bordered">
    <thead>
     <tr>
      <th class="align-middle">Name</th>
      <th class="align-middle">Team</th>
      <th class="align-middle">Week</th>
      <th class="align-middle">Score 1</th>
      <th class="align-middle">Score 2</th>
      <th class="align-middle">Score 3</th>
      <th class="align-middle">Score 4</th>
      <th class="align-middle">Score 5</th>
      <th class="align-middle">Score 6</th>
      <th class="align-middle">Score 7</th>
      <th class="align-middle">Score 8</th>
     </tr>
    </thead>
    <tbody>
    <?php
     $sql = "SELECT * FROM member ORDER BY  member_name ASC";
     $result = mysqli_query($db,$sql) or die("Database access failed: " . mysqli_error());
     while ($team = mysqli_fetch_assoc($result)) {  
    ?>
    <tr >
     <td class="align-middle"><input type="text" name="scoring_1" value="<?php echo $team["member_name"]; ?>" readonly hidden>  <?php echo $team["member_name"]; ?></td>
     <td class="align-middle"><input type="text" name="scoring_2" value="<?php echo $team["member_team"]; ?>" readonly hidden>  <?php echo $team["member_team"]; ?></td>
     <td class="align-middle"><input type="text" name="scoring_3" value="" readonly hidden> </td>
     <td class="align-middle"><input type="checkbox" name="scoring_4" value="5"></td>
     <td class="align-middle"><input type="checkbox" name="scoring_5" value="10"></td>
     <td class="align-middle"><input type="checkbox" name="scoring_6" value="5"></td>
     <td class="align-middle"><input type="checkbox" name="scoring_7" value="5"></td>
     <td class="align-middle"><input type="checkbox" name="scoring_8" value="5"></td>
     <td class="align-middle"><input type="checkbox" name="scoring_9" value="5"></td>
     <td class="align-middle"><input type="checkbox" name="scoring_10" value="20"></td>
     <td class="align-middle"><input type="checkbox" name="scoring_11" value="50"></td>
    </tr>
        <?php
        }
        ?>
    </tbody>
   </table>
  </div>
   <div class="form-row mb-3">
    <button type="submit" class="btn btn-primary btn-block" name="score_add_btn">Add Score</button>
   </div>
 </form>

将表添加到 SQL 的函数

/ call the team_edit() function if team_edit_btn is clicked
if (isset($_POST['score_add_btn'])) {
    score_add();
}

// LOGIN USER
function score_add(){
    global $db, $errors, $member_id, $member_name_edit, $member_team_edit, $members_view_url;
    // grap form values
    $scoring_1 = $_POST['scoring_1'];
    $scoring_2 = $_POST['scoring_2'];
    $scoring_3 = $_POST['scoring_3'];
    $scoring_4 = $_POST['scoring_4'];
    $scoring_5 = $_POST['scoring_5'];
    $scoring_6 = $_POST['scoring_6'];
    $scoring_7 = $_POST['scoring_7'];
    $scoring_8 = $_POST['scoring_8'];
    $scoring_9 = $_POST['scoring_9'];
    $scoring_10 = $_POST['scoring_10'];
    $scoring_11 = $_POST['scoring_11'];
    // make sure form is filled properly
    if (empty($scoring_1)) {
        array_push($errors, "Name is required");
    }
    if (count($errors) == 0)    {
        $query = "INSERT INTO scoring (scoring_1, scoring_2, scoring_3, scoring_4, scoring_5, scoring_6, scoring_7, scoring_8, scoring_9, scoring_10, scoring_11 )
        VALUES ('$scoring_1', '$scoring_2', '$scoring_3', '$scoring_4', '$scoring_5', '$scoring_6', '$scoring_7', '$scoring_8', '$scoring_9', '$scoring_10', '$scoring_11')";
        mysqli_query($db, $query);
        $_SESSION['success']  = "<h4>Done</h4>";
        header("location: $leaderboard_menmber_url"); 
    }else {
        $_SESSION['failure']  = "Error updating record: " . $db->error;
        header("location: $leaderboard_menmber_url");
    }
    $db->close();

}

问题

该函数只将动态html表的最后一行添加到数据库中。

期望的结果。

动态 HTML 表中的每个条目都需要作为自己的条目添加到 MySQL。

Answer 1

<input type="text" name="scoring_1" value="<?php echo $team["member_name"]; ?>

在这里您将变量名称设置为scoring_1，但表的下一行将覆盖它（相反，浏览器可能会发送数据，但php会创建一个变量scoring_1并将给定值之一分配给它们。解决这个问题将名称设置为scoring_1[] <input type="text" name="scoring_1[]" value="<?php echo $team["member_name"]; ?>

这说 php 创建一个数组并将值存储在那里。此外，当您使用团队 ID 作为行索引并使用固定数字作为二维数组中的列时，您可以改进您的代码

<input type="text" name="scoring[<?php echo $team["id"];>][1]" value="<?php echo $team["member_name"]; ?>