嵌套表单验证 rails 3.2

Question

我在同一个视图中有一个工作和用户（设计）表单。当我尝试在用户字段中提交错误时，它会给我一个带有验证消息的异常页面。在工作字段中提交错误可以正常工作！

job_controller.rb
def new
  @job = Job.new
  if !current_user
    @job.user = User.new
  end

  respond_to do |format|
    format.html # new.html.erb
  end
end

  def create
    @types = Type.all
    @categories = Category.all

    @job = Job.new(params[:job])
    #if not logged in creates a user and sign in
    if !current_user
      @user = User.new(params[:job][:user_attributes])
    else
      @user = current_user
    end

    @job.user_id = @user.id

    respond_to do |format|
      if @job.save
        if !current_user
          sign_in(:user, @user)
        end
        format.html { redirect_to @job }
      else
        format.html { render action: "new" }
      end
    end
  end

  job.rb
  attr_accessible :user_attributes, :description, :name ....
  belongs_to :user
  accepts_nested_attributes_for :user

谢谢！

Answer 1

因为您正在调用 @user.save!，这将产生异常。这样做也不会将作业与用户放在同一事务中。你要的是nested_attributes:

class Job < ActiveRecord::Base

   accepts_nested_attributes_for :user

end

如果用户已登录，请不要显示表单的该部分并过滤这些参数。

在http://api.rubyonrails.org/classes/ActiveRecord/NestedAttributes/ClassMethods.htmlhttp://api.rubyonrails.org/classes/ActiveRecord/NestedAttributes/ClassMethods.html处查看更多 Rails 文档

编辑：

简化您的控制器代码，因为您使用的是嵌套属性，您不再需要手动创建用户。

#if not logged in creates a user and sign in
if !current_user
  @user = User.new(params[:job][:user_attributes]) # this is no longer needed
else
  @user = current_user
end

@job.user_id = @user.id # this is redundant

类似于：

# if logged in, manually assign the user (also you may want to reject any user attributes)
@job.user = current_user if current_user