我将如何获得三行的平均值。 (SQL)

Question

我能够得到我需要的三个医院的结果。知道我试图弄清楚如何将三个结果平均在一起以获得整体组结果。

   SELECT H.[Hospital Name],
    Format(1.0* Avg (Case When s.[PhysicianQuestion]>3 Then 1.0 Else 0 End),'P2') As    [Physician 
   Top Box],
   Format(1.0*Avg (Case When s.[NurseQuestion]=4 Then 1.0 Else 0 End),'P2') As [Nurse Top Box],
  Format( 1.0*Avg ( Case When s.[FacilityQuestion]=4 Then 1.0 Else 0 end),'P2') As [Facility Top Box]
  From surveyresponses as S
  Join Visits as V  on v.AccountNumber=S.AccountNumber
   join Hospitals as H on  H.HospitalID=V.HospitalID
   Group By [Hospital Name] 
   Order By [Hospital Name]


     Results 
     Central Hospital       74.04%  76.15%  71.26%
      Desert Flats Hospital 67.79%  68.99%  73.96%
     Mercy Valley Hospital  74.93%  76.45%  73.88%

Answer 1

如果需要得到医院工作人员的整体表现

select [Hospital Name],
    format( (([Physician Top Box] + [Nurse Top Box] + [Facility Top Box] )/3), 'P2') AS
    [Overall Hospital Performance]
from (
    select 
        h.[Hospital Name],
        avg(case when s.PhysicianQuestion > 3 then 1.0 else 0 end) As [Physician Top Box],
        avg(case when s.NurseQuestion = 4     then 1.0 else 0 end) As [Nurse Top Box],
        avg(case when s.FacilityQuestion = 4  then 1.0 else 0 end) As [Facility Top Box]
    from surveyresponses as s
    inner join Visits as v    on v.AccountNumber = s.AccountNumber
    inner join Hospitals as h on h.HospitalID    = v.HospitalID
    group by h.[Hospital Name]
) t

Answer 2

如果我正确地关注了你，你可以添加另一个级别的聚合：

select
    format(avg([Physician Top Box]), 'P2') [Avg Physician Top Box],
    format(avg([Nurse Top Box]),     'P2') [Avg Nurse Top Box],
    format(avg([Facility Top Box]),  'P2') [Avg Facility Top Box]
from (
    select 
        h.[Hospital Name],
        avg(case when s.PhysicianQuestion > 3 then 1.0 else 0 end) As [Physician Top Box],
        avg(case when s.NurseQuestion = 4     then 1.0 else 0 end) As [Nurse Top Box],
        avg(case when s.FacilityQuestion = 4  then 1.0 else 0 end) As [Facility Top Box]
    from surveyresponses as s
    inner join Visits as v    on v.AccountNumber = s.AccountNumber
    inner join Hospitals as h on h.HospitalID    = v.HospitalID
    group by h.[Hospital Name]
) t

请注意，在进行了所有人工计算之后，我将格式移到了外部查询。

---

另一方面，如果你想要查询返回的每一行的三列值的平均值，你可以这样做：

select
    [Hospital Name],
    format([Physician Top Box], 'P2') [Physician Top Box],
    format([Nurse Top Box],     'P2') [Nurse Top Box],
    format([Facility Top Box],  'P2') [Facility Top Box],
    ([Physician Top Box] + [Nurse Top Box] + [Facility Top Box]) / 3 [Avg Top Box]
from (
    select 
        h.[Hospital Name],
        avg(case when s.PhysicianQuestion > 3 then 1.0 else 0 end) As [Physician Top Box],
        avg(case when s.NurseQuestion = 4     then 1.0 else 0 end) As [Nurse Top Box],
        avg(case when s.FacilityQuestion = 4  then 1.0 else 0 end) As [Facility Top Box]
    from surveyresponses as s
    inner join Visits as v    on v.AccountNumber = s.AccountNumber
    inner join Hospitals as h on h.HospitalID    = v.HospitalID
    group by h.[Hospital Name]
) t

请注意，这里的子查询不是绝对必要的；它只是避免了多次重复条件表达式。