计算平均值时重置总和

Question

我有一个程序询问用户他们想输入多少个测验，存储成绩，然后计算平均值。成绩必须在 0 到 100 之间。但是，当我输入高于 100 的成绩时，平均成绩是错误的。它不会重置总和。如果我输入 120 并提示我重新输入成绩，它在计算平均值时仍然使用 120。如何让它重置？

注意：我不想更改格式（例如使用 while 循环）。

#include <iostream>
using namespace std;
int main(){
    int n, i;
    float num[13], sum=0.0, average;
    cout << "Enter the numbers of quizzes from 1-13: ";
    cin >> n;

while (n < 1 || n > 13)
{
    cout << "You must enter a number from 1 - 13." << endl;
    cout << "Enter the number of quizzes you would like to input(1-13): “;
    cin >> n;

}


for(i=0; i<n; ++i)
  {
       cout << i+1 << ". Enter number: ";
       cin >> num[i];
       sum+=num[i];


    while (num[i] < 0 || num[i] > 100)
    {
    cout << “You must enter a number between 0 and 100. Re enter scores.”;
        cout << i+1 << ". Enter number: ";
        cin >> num[i];
    }
  }

   average=sum/n;
   cout << "Average = " << average;
   return 0;
}

Answer 1

只需将sum+=num[i] 放在while (num[i] < 0 || num[i] > 100) ... 循环后面！

这样你只对有效数字求和。

for(i=0; i<n; ++i)
{
   cout << i+1 << ". Enter number: ";
   cin >> num[i];
   //sum+=num[i]; remove here !!

   while (num[i] < 0 || num[i] > 100)
   {
    cout << “You must enter a number between 0 and 100. Re enter scores.”;
    cout << i+1 << ". Enter number: ";
    cin >> num[i];
   }

   sum+=num[i]; // <- insert here
}

Answer 2

for(i=0; i<n; ++i)
  {
       cout << i+1 << ". Enter number: ";
       cin >> num[i];

    while (num[i] < 0 || num[i] > 100)
    {
    cout << “You must enter a number between 0 and 100. Re enter scores.”;
        cout << i+1 << ". Enter number: ";
        cin >> num[i];
    }
  }


   sum+=num[i];
   average=sum/n;
   cout << "Average = " << average;
   return 0;
}