如何在每次循环迭代中创建一个新的 JSON 对象

Question

我正在开发一项功能，根据我的日常工作时间以及我的合同的开始和结束日期在日历中显示我的工作时间。问题是当我在同一天有 2 个或更多班次时。假设朱利安从 2019 年 7 月 17 日到 2019 年 7 月 31 日每周一从 03:00 到 04:00 和同一天从 5:00 到 6:00 换班。这意味着我的日历应该显示这 2 次轮班在 7 月 22 日和 7 月 29 日。我已经编写了逻辑来让我得到正确的日期。截至目前，我的 JSON 响应看起来像这样

{"user":"Julian","start":"2019-07-22","day":"Monday","start_time":["03:00","05:00"], "end_time":["04:00","06:00"]},{"user_":"Julian","start":"2019-07-29","day":"Monday","start_time ":["03:00","05:00"],"end_time":["04:00","06:00"]}

这是由我的 JSON 构建器文件中的以下代码生成的

        json.array! event.each do |inevent|

              json.id hr_schedule.id
              json.user_id hr_schedule.user_id

              json.start inevent.strftime('%Y-%m-%d') 
              day_of_week = inevent.strftime('%A') 
              json.day day_of_week
              if day_of_week == "Monday"
                  json.start_time hr_schedule.monday_st
                  json.end_time hr_schedule.monday_end  
              elsif day_of_week == "Tuesday"
                  json.start_time hr_schedule.tuesday_st
                  json.end_time hr_schedule.tuesday_end               
              elsif day_of_week == "Wednesday"
                  json.start_time hr_schedule.wednesday_st
                  json.end_time hr_schedule.wednesday_end   
              elsif day_of_week == "Thursday"

                  json.start_time hr_schedule.thursday_st
                  json.end_time hr_schedule.thursday_end    
              elsif day_of_week == "Friday"

                  json.start_time hr_schedule.friday_st
                  json.end_time hr_schedule.friday_end  

              elsif day_of_week == "Saturday"
                  json.start_time hr_schedule.saturday_st
                  json.end_time hr_schedule.saturday_end    
              elsif day_of_week == "Sunday" 
                  json.start_time hr_schedule.sunday_st
                  json.end_time hr_schedule.sunday_end  
              end



     end    

我想要实现的是能够将我的所有事件作为一个唯一的 JSON 对象，如下所示

{"user":"Julian","start":"2019-07-22","day":"Monday","start_time":"03:00","end_time":"04:00 "},{"user":"Julian","start":"2019-07-22","day":"Monday","start_time":"05:00","end_time":"06:00 "}, {"user":"Julian","start":"2019-07-29","day":"Monday","start_time":"03:00","end_time":"04:00"}, {"user":"Julian","start":"2019-07-29","day":"Monday","start_time":"05:00","end_time":"06:00"}

Answer 1

我不确定json 是什么类，也不确定array! 在做什么。但是做你想做的事情的基本方法是使用map 将你的事件变成一个哈希数组。然后使用to_json将数组转换成JSON。

calendar = event.map do |inevent|
  json = {}

  json[:id] = hr_schedule.id
  json[:user] = hr_schedule.user_id

  json[:start] = inevent.strftime('%Y-%m-%d') 
  json[:day] = inevent.strftime('%A')

  case inevent.wday
  when 0
    json[:start_time] = hr_schedule.sunday_st
    json[:end_time] = hr_schedule.sunday_end  
  when 1
    json[:start_time] = hr_schedule.monday_st
    json[:end_time] = hr_schedule.monday_end  
  when 2
    json[:start_time] = hr_schedule.tuesday_st
    json[:end_time] = hr_schedule.tuesday_end               
  when 3
    json[:start_time] = hr_schedule.wednesday_st
    json[:end_time] = hr_schedule.wednesday_end   
  when 4
    json[:start_time] = hr_schedule.thursday_st
    json[:end_time] = hr_schedule.thursday_end    
  when 5
    json[:start_time] = hr_schedule.friday_st
    json[:end_time] = hr_schedule.friday_end  
  when 6
    json[:start_time] = hr_schedule.saturday_st
    json[:end_time] = hr_schedule.saturday_end    
  end

  json
end

puts calendar.to_json

我使用case/when 和Time#wday 对其进行了一些简化。如果应用程序的语言发生变化，strftime(%A) 可能会发生变化，并且星期几的数字更难打错。

---

附带说明，此事件结构仅限于在午夜之前结束的事件。考虑改为使用完整的 ISO8061 日期时间作为开始和结束时间。一般来说，使用完整的日期时间比使用单独的日期和时间更容易。活动日期可以从start推断出来。

{"user":"Julian","start":"2019-07-22T03:00","end":"2019-07-22T04:00"}

或者，如果事件是相对的，例如每周一发生，请考虑开始和duration。并使用ISO weekday number 代替字符串，减少接收者的解析。

{"user":"Julian","day":1,"start":"03:00","duration":"P1H"}