【发布时间】:2016-05-18 08:48:59
【问题描述】:
我在尝试使用 scipy.stats.multivariate_normal 时遇到问题,希望你们中的某个人能提供帮助。
我有一个 2x2 矩阵,可以找到使用 numpy.linalg.inv() 的逆矩阵,但是当我尝试将它用作 multivariate_normal 中的协方差矩阵时,我收到一个 LinAlgError 说明它是一个奇异矩阵:
In [89]: cov = np.array([[3.2e5**2, 3.2e5*0.103*-0.459],[3.2e5*0.103*-0.459, 0.103**2]])
In [90]: np.linalg.inv(cov)
Out[90]:
array([[ 1.23722158e-11, 1.76430200e-05],
[ 1.76430200e-05, 1.19418880e+02]])
In [91]: multivariate_normal([0,0], cov)
---------------------------------------------------------------------------
LinAlgError Traceback (most recent call last)
<ipython-input-91-44a6625beda5> in <module>()
----> 1 multivariate_normal([0,0], cov)
/mnt/ssd/Enthought_jli199/Canopy_64bit/User/lib/python2.7/site-packages/scipy/stats/_multivariate.pyc in __call__(self, mean, cov, allow_singular, seed)
421 return multivariate_normal_frozen(mean, cov,
422 allow_singular=allow_singular,
--> 423 seed=seed)
424
425 def _logpdf(self, x, mean, prec_U, log_det_cov, rank):
/mnt/ssd/Enthought_jli199/Canopy_64bit/User/lib/python2.7/site-packages/scipy/stats/_multivariate.pyc in __init__(self, mean, cov, allow_singular, seed)
591 """
592 self.dim, self.mean, self.cov = _process_parameters(None, mean, cov)
--> 593 self.cov_info = _PSD(self.cov, allow_singular=allow_singular)
594 self._dist = multivariate_normal_gen(seed)
595
/mnt/ssd/Enthought_jli199/Canopy_64bit/User/lib/python2.7/site-packages/scipy/stats/_multivariate.pyc in __init__(self, M, cond, rcond, lower, check_finite, allow_singular)
217 d = s[s > eps]
218 if len(d) < len(s) and not allow_singular:
--> 219 raise np.linalg.LinAlgError('singular matrix')
220 s_pinv = _pinv_1d(s, eps)
221 U = np.multiply(u, np.sqrt(s_pinv))
LinAlgError: singular matrix
【问题讨论】:
-
你使用哪个版本的 numpy?我可以在 numpy 1.10.1 上成功运行代码。请注意,尽管矩阵在技术上是可逆的,但它的缩放比例非常糟糕。
-
嗨 kazemakase,它的版本是 1.9.2。
标签: python numpy scipy statistics linear-algebra