将 pandas DataFrame DatetimeIndex 延长 25 个工作日

Question

我一直在尝试将我的 Pandas DataFrame 日期索引延长 25 个工作日。我编写的以下测试示例演示了该问题。工作日已正确生成，但并未附加到 DataFrame。

import pandas as pd
from business_calendar import Calendar

dates = pd.date_range('20190121', periods=5)
df = pd.DataFrame({'high': (58.22, 57.93, 57.51, 57.89, 58.77), 'low': (57.65, 57.15, 56.98, 57.12, 58.00)}, index=dates)

cal = Calendar()
last_idx = df.index[-1].date()
for i in range(1, 26):
    weekdays = pd.DatetimeIndex([cal.addbusdays(last_idx, i)])
    print("idx_count: {:2d} idx: {}".format(i, weekdays))
    df.index.append(weekdays)
print(df.index)

代码以 0 级错误退出，知道为什么 DataFrame 没有按预期更新吗？

Answer 1

您正在尝试以工作日为索引向 Dataframe 添加行，因此一种简单的方法是

for i in range(1, 26):
   weekdays = pd.DatetimeIndex([cal.addbusdays(last_idx, i)])
   #If you want the values to be na
   newRow = pd.DataFrame(index=weekdays)
   #Or if you want to give values to the new rows
   newRow = pd.DataFrame({'high': (42), 'low': (0)}, index=weekdays)

   df = df.append(newRow)

del newRow
print(df.index)

---

Answer 2

对代码做了一些改动（cmets中的解释）：

import pandas as pd
from business_calendar import Calendar

dates = pd.date_range('20190121', periods=5)
df = pd.DataFrame({'high': (58.22, 57.93, 57.51, 57.89, 58.77), 'low': (57.65, 57.15, 56.98, 57.12, 58.00)}, index=dates)

cal = Calendar()
last_idx = df.index[-1].date()
idx_list=[] #added this line
for i in range(1, 26):
    weekdays = pd.DatetimeIndex([cal.addbusdays(last_idx, i)])
    #print(weekdays[0])
    idx_list.append(weekdays[0]) #appending just the value so weekdays[0]
idx_list.extend(df.index) #extend the list with index
df.reindex(idx_list).sort_index() #reindex the df and sort the index

            high    low
2019-01-21  58.22  57.65
2019-01-22  57.93  57.15
2019-01-23  57.51  56.98
2019-01-24  57.89  57.12
2019-01-25  58.77  58.00
2019-01-28    NaN    NaN
2019-01-29    NaN    NaN
2019-01-30    NaN    NaN
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