如何使用 Python3 删除括号和所有数据

Question

我正在尝试使用 Python 3 删除括号和所有数据。

我研究了几个不同的主题，包括这里：

How to remove parentheses and all data within using Pandas/Python?

终于得到之后：

re.sub(r"\(.*\)|\s-\s.*", r"", str1)

为了运行没有错误，它没有从 str1 字符串中删除内容。

然后我尝试了这种方法：

How to remove text within parentheses from Python string?

在读取文件并存储到 str1 之前从文件中删除括号和内容 - 但我收到此错误：

Traceback (most recent call last):

  File "sum_all.py", line 27, in <module>
    data.append(line.replace(match.group(),'').strip())
AttributeError: 'NoneType' object has no attribute 'group'

这是代码，我显然是新手，感谢任何帮助！

# Python3 program to calculate sum of 
# all numbers present in a str1ing 
# containing alphanumeric characters 

# Function to calculate sum of all 
# numbers present in a str1ing 
# containing alphanumeric characters 
import re
import math
import pyperclip
import pandas
def find_sum(str1): 
    # Regular Expression that matches digits in between a string 
    return sum(map(int,re.findall('\d+',str1))) 

def find_sum2(str2): 
    # Regular Expression that matches digits where hr follows short for hours 
    return sum(map(int,re.findall('(\d+)hr',str1)))

str2=0

# Regular Expression 
data=[]
pattern=r'\(.+\)|\s\-.+'
with open('project.txt','r') as f:
    for line in f:
        match=re.search(pattern,line)
        data.append(line.replace(match.group(),'').strip())

print(data)

# input alphanumeric str1ing 
with open ("project.txt", "r") as myfile:
    str1=myfile.read().replace('\n', '')


# Regular Expression that removes (*) and Normalizes White Space - didn't work
#re.sub(r"\(.*\)|\s-\s.*", r"", str1)

# Regular Expression that removes (*) - didn't work
#re.sub(r"\(.*\)", r"", str1)

Answer 1

你可以试试这个。 r"\((.*?)\)"

\( 和 \) 表示我们要定位实际的括号。

然后表达式(.*?) 周围的括号表示我们想要对里面的内容进行分组。

最后，.*? 表示我们想要任何字符 . 以及该字符 *? 的任何重复。

s = "start (inside) this is in between (inside) end"
res = re.sub(r"\((.*?)\)", "", s)
print(res) 

打印

'start  this is in between  end'

希望对您有所帮助。