C中循环中的动态数组[关闭]

Question

我想创建一个代码，该代码将根据用户需求存储新数组并对其执行特定的操作集。所以，考虑到一旦操作完成后我真的不需要存储该数组，我想覆盖同一个数组，但这就是我遇到问题的地方。

int main() 
{
    int i, T;

    scanf("%d", &T);
    int res[T];//for T cases I'll have T outputs so saving it in an array

    for(i=0; i<T; i++)
    {
        int size, j;
        scanf("%d", &size);
        int ary[size];
        for(j=0; j<size; j++)
        {
            scanf("%d ", &ary[j]);
        }
        //In each case I'm just declaring an array and getting a result n storing in another array
        res[i]=fn(ary, size);//fn returns 1 if array forms Circular Prime else 0
    }

    for(i=0; i<T; i++)
    {
        if(res[i]==1)
            printf("YES\n");
        else
            printf("NO\n");            
    }
    return 0;
}

Answer 1

C89 不允许使用非常量绑定说明符创建数组。 C99 引入了这个概念，C11 将其作为可选功能。为了 100% 可移植，您应该使用动态内存分配来解决这个问题：

int main() {
    int i, T;
    scanf("%d", &T);
    //DYNAMIC MEMORY ALLOCATION
    int *res = malloc(T * sizeof(int)); //for T cases I'll have T outputs so saving it in an array
    if (res == NULL) { //Check for failure
        /* failure, out of memory */
        return 1;
    }
    for(i=0; i<T; i++){
        int size, j;
        scanf("%d", &size);
        //DYNAMIC MEMORY ALLOCATION
        int *ary = malloc(size * sizeof(int));
        if (ary == NULL) { //Check for failure
            /* failure, out of memory */
            return 1;
        }
        for(j=0; j<size; j++){
            scanf("%d", &ary[j]);
        } //In each case I'm just declaring an array and getting a result n storing in another array
        res[i]=fn(ary, size);//Called a function got a result stored in res[]
        //FREE ALLOCATED MEMORY
        free(ary);
    }
    for(i=0; i<T; i++){
        if(res[i]==1)
            printf("YES\n");
        else
            printf("NO\n");            
    }
    //FREE ALLOCATED MEMORY
    free(res);
    return 0;
}