【发布时间】:2015-12-02 21:25:38
【问题描述】:
我遇到了 printf 的问题。我想打印出两个单独的双精度数组并将小数位限制为一位,但出现错误。 第一个数组将打印摄氏温度,第二个数组将获取这些值并将它们更改为华氏温度,该值也将打印到屏幕上。当数字被打印出来时,我正在尝试实现 printf 方法。我能想到的唯一问题是我引用的是数组中的索引值,而不是实际上的双精度值。
import java.util.Scanner;
public class tempOne {
public static void main (String [] args){
Scanner sc = new Scanner(System.in);
double [] temp1 = new double [10];
double [] temp2 = new double[10];
System.out.println("Please enter 10 temperatures in Celsius: ");
for (int index = 0; index<temp1.length;index++)//Gets temperatures in Celsius.
{
temp1[index]=sc.nextDouble();
}
for (int index = 0; index<temp1.length;index++)//Prints temperatures in Celsius.
{
System.out.printf("Temperatures in Celsius: %.1f", temp1[index] + " ");
}
for (int index = 0; index<temp1.length;index++)//Copies array 1 into array 2.
{
temp2[index]=temp1[index];
}
System.out.println("");
for (int index = 0; index<temp1.length;index++)//Changes values in array 2 to Farenheit.
{
temp2[index] = ((temp1[index]*9/5)+32);
}
for (int index = 0; index<temp1.length;index++)
{
System.out.printf("Temperatures in Farenheit: %.1f", temp2[index] + " ");//Prints array 2.
}
}
}
结果如下:
Please enter 10 temperatures in Celsius:
20.22
Temperatures in Celsius: Exception in thread "main" java.util.IllegalFormatConversionException: f != java.lang.String
at java.util.Formatter$FormatSpecifier.failConversion(Formatter.java:4302)
at java.util.Formatter$FormatSpecifier.printFloat(Formatter.java:2806)
at java.util.Formatter$FormatSpecifier.print(Formatter.java:2753)
at java.util.Formatter.format(Formatter.java:2520)
at java.io.PrintStream.format(PrintStream.java:970)
at java.io.PrintStream.printf(PrintStream.java:871)
at tempOne.main(tempOne.java:16)
有人知道这里发生了什么吗?
【问题讨论】: