【发布时间】：2014-08-07 23:38:03
【问题描述】：
好的，这是我的问题...我几乎完成了我制作的小游戏，但我想测试它是否适用于“调试作弊”，以查看程序是否实际上向您显示了正确的数字。
我设置了 srand(time(0)) ，这样当你玩游戏时，程序显然每次都会使数字选择不同。不过，它显然会不断生成不同的数字，因为系统时间在变化。
正如您在代码中看到的，我有一个名为“ANSWER”的变量，即 Range(low,high)。检查名为“guessN”的用户输入变量以查看它是否与“ANSWER”匹配。如果是这样，那么程序会说用户赢得了游戏，我相信这是有效的。
问题是当我想要程序时首先显示答案是什么，恰好是 47，当我输入 47 时，它实际上是错误的，因为时间生成器仍在运行并且已经是 37 岁了。
我需要什么帮助：目前有没有办法暂停生成，直到用户输入他的答案？..
提前感谢您对我的帮助！ :)
屏幕截图：
http://i.imgur.com/mVRSWCU.png
#include <iostream>
#include <iomanip>
#include <string>
#include <cstdlib> // For srand and rand
using namespace std;
/*Guessing Game: Program generates random #'s,
user has 3 chances to guess one number at a time,
otherwise the Computer wins.
*/
static unsigned int rangevalue;
void NewRange(int nLow, int nHigh) // Range for generated #'s.
{
rangevalue = (rand() % (nHigh - nLow + 1)) + nLow;
}
unsigned int getRange()
{
return rangevalue;
}
//DON'T GET LOST!
string DescRange; // Descriptive Range
string SelectionInput;
int low = 1;
int high;
//DON'T GET LOST!
void NumberGen()
{
do
{
cout << "Guess a number in between...\n " << endl;
cout << "1.) 1-5\t\t[EASY]" << endl;
cout << "2.) 1-10\t[MEDIUM]" << endl;
cout << "3.) 1-50\t[HARD]" << endl;
cout << "4.) 1-100\t[IMPOSSIBLE]" << endl;
cout << "\n5.) Choose a custom range? *" << endl;
cout << "6.) EXIT \n" << endl;
cout << "=> ";
getline(cin, SelectionInput);
} while (
SelectionInput != "1" && SelectionInput != "2" && SelectionInput != "3" && SelectionInput != "4" && SelectionInput != "5" && SelectionInput != "6"
&& SelectionInput != "EASY" && SelectionInput != "Easy" && SelectionInput != "easy"
&& SelectionInput != "MEDIUM" && SelectionInput != "Medium" && SelectionInput != "medium"
&& SelectionInput != "HARD" && SelectionInput != "Hard" && SelectionInput != "hard"
&& SelectionInput != "IMPOSSIBLE" && SelectionInput != "Impossible" && SelectionInput != "impossible"
&& SelectionInput != "CUSTOM" && SelectionInput != "Custom" && SelectionInput != "custom"
&& SelectionInput != "EXIT" && SelectionInput != "Exit" && SelectionInput != "exit"
);
if (SelectionInput == "1" || SelectionInput == "EASY" || SelectionInput == "Easy" || SelectionInput == "easy")
{
high = 5;
DescRange = "1-5";
cout<<"\t[Input was \"" << SelectionInput << "\"]\n\n" << endl;
}
else if (SelectionInput == "2" || SelectionInput == "MEDIUM" || SelectionInput == "Medium" || SelectionInput == "medium")
{
high = 10;
DescRange = "1-10";
cout<<"\t[Input was \"" << SelectionInput << "\"]\n\n" << endl;
}
else if (SelectionInput == "3" || SelectionInput == "HARD" || SelectionInput == "Hard" || SelectionInput == "hard")
{
high = 50;
DescRange = "1-50";
cout<<"\t[Input was \"" << SelectionInput << "\"]\n\n" << endl;
}
else if (SelectionInput == "4" || SelectionInput == "IMPOSSIBLE" || SelectionInput == "Impossible" || SelectionInput == "impossible")
{
high = 100;
DescRange = "1-100";
cout<<"\t[Input was \"" << SelectionInput << "\"]\n\n" << endl;
}
else if (SelectionInput == "5" || SelectionInput == "CUSTOM" || SelectionInput == "Custom" || SelectionInput == "custom")
{
cout<<"\t[Input was \"" << SelectionInput << "\"]\n\n" << endl;
cout << "Input a digit range for you to guess a number in between. " << endl;
cout << "Low: ";
cin >> low;
cout << "High: ";
cin >> high;
}
else if (SelectionInput == "6" || SelectionInput == "EXIT" || SelectionInput == "Exit" || SelectionInput == "exit")
{
high = 10;
cout << "\nYou've chosen to terminate the program!" << "\t[Input was \"" << SelectionInput << "\"]\n\n" << endl;
for (int iii = 0; iii < 5; iii++)
{
cout << "The program will now collapse..." << endl;
}
cout << "\n" << endl;
}
NewRange;
int ANSWER = getRange();
cout << "For debugging/test purposes, the range is: \"" << ANSWER << "\". \n" << endl; // DEBUG for knowing what the 'ANSWER' is.
}
void Guessing()
{
NumberGen();
int ANSWER = getRange(); // Making things SIMPLE
int guessN;
if (SelectionInput == "5" || SelectionInput == "CUSTOM" || SelectionInput == "Custom" || SelectionInput == "custom")
{
cout << "Guess the number I picked between " << low << "-" << high << ": ";
cin >> guessN;
if (guessN == ANSWER)
cout << "Oh no, you won! The answer \"" << guessN << "\", is... correct! \n\n" << endl;
else
cout << "\nSorry you lose, try again! Answer was " << ANSWER << ". \n\n" << endl;
}
else
{
cout << "Guess the number I picked between " << DescRange << ": ";
cin >> guessN;
if (guessN == ANSWER)
cout << "Oh no, you won! The answer \"" << guessN << "\", is... correct! \n\n" << endl;
else
cout << "\nSorry you lose, try again! Answer was "<<ANSWER<<". \n\n" << endl;
}
}
int main()
{
srand(time(0));
Guessing();
//system("PAUSE"); // * Temporarily Disabled *
return 0;
}
【问题讨论】：
-
NumberGen有一个int Answer，而Guessing有一个完全不同的int ANSWER变量，它们分别被初始化。为什么你会期望这些数字是一样的。 -
其实我是这么想的！不过，我将如何解决这个问题，因为显然 srand(time(0)) 必须在 int ANSWER 之前声明
-
srand() 只是随机生成器的种子——你根本不需要调用它，只要你每次都能得到相同的“随机”数字序列——所以移动srand() 到 main，只有在你真正想要一个新范围时才调用你的“范围”函数。
-
但是如果人们再次玩这个游戏，他们不会得到同样的可预测答案吗？不会有什么不同。
-
@Jordan -- 是的，他们会的 -- 这就是为什么我说“只要你对获得相同的序列感到满意”。如果不是，您只需要在程序的生命周期中播种一次，而不是在执行 rand() 之前的每次调用中播种 - 如果您播种多次，您实际上将面临每次 rand() 调用获得相同数字的风险，如果您经常这样做，并且每次调用都会重置生成器。