将数据从列表传输到二维数组

Question

我有一个 Java 代码，它将从包含多个句子的字符串中提取一个唯一的单词，并计算每个句子中单词的出现次数。

这是用于实现此目的的 Java 编码。或者，您可以尝试here。

import java.util.*;

class Main {
  public static void main(String[] args) {
    String someText = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but also the leap into electronic typesetting, remaining essentially unchanged. It was popularised in the 1960s with the release of Letraset sheets containing Lorem Ipsum passages, and more recently with desktop publishing software like Aldus PageMaker including versions of Lorem Ipsum.";

    List<List<String>> sort = new ArrayList<>();
    Map<String, ArrayList<Integer>> res = new HashMap<>();

    for (String sentence : someText.split("[.?!]\\s*"))
    {
        sort.add(Arrays.asList(sentence.split("[ ,;:]+"))); //put each sentences in list
    }

    int sentenceCount = sort.size();
    for (List<String> sentence: sort) {
        sentence.stream().forEach(s -> res.put(s, new ArrayList<Integer>(Collections.nCopies(sentenceCount, 0))));
    }
    int index = 0;
    for (List<String> sentence: sort) {
        for (String s : sentence) {
            res.get(s).set(index, res.get(s).get(index) + 1);
        }
        index++;
    }
    System.out.println(res);
  }
}

代码的输出是这样的：

{standard=[0, 1, 0, 0], but=[0, 0, 1, 0], ..... }

这意味着“标准”这个词没有出现在第 1 句中，在第 2 句中出现了 1 次，在第 3 和第 4 句中没有出现。

但是，数据在列表中。我如何将数据转换成二维矩阵的形式，使其变得有点像这样：

    double[][] multi = new double[][]{
          { 0, 1, 0, 0 },
          { 0, 0, 1, 0 },
          { 0, 1, 0, 0 },
          { 0, 0, 1, 0 },
          { 0, 0, 1, 0 } } //data stored in a 2D array named multi

感谢您对此的帮助。谢谢。

Answer 1

循环中的循环应该可以做到。此代码假定每行都具有相同数量的元素（它们应该是因为每个单词有相同数量的可能句子）。我添加了键的 ArrayList，以便您稍后可以引用它们以了解矩阵中的哪个行索引对应于给定的单词。

ArrayList<String> keys = new ArrayList<String>(res.keySet());
int rowSize = keys.size();
int colSize = res.get(keys.get(0)).size();
double [][] multi = new double[rowSize][colSize];
for (int rowIndex = 0; rowIndex < rowSize; rowIndex++) {
    String key = keys.get(rowIndex);
    List<Integer> row = res.get(key);
    for (int colIndex = 0; colIndex < colSize; colIndex++) {
        multi[rowIndex][colIndex] = row.get(colIndex);
    }
}

我将数组加倍，因为这就是问题所在，但似乎整数会更合适。

对此答案的先前版本表示歉意；我正在查看您尝试聚合的错误对象。