【问题标题】:Fitting Gamma distribution to data in R using optim, ML使用 optim, ML 将 Gamma 分布拟合到 R 中的数据
【发布时间】:2015-10-06 17:39:42
【问题描述】:

我对 R 有点陌生。我有一个数据集,其中还包括家庭收入数据,我必须使用最大似然估计来拟合该数据的 Gamma 分布。明确告知我们需要使用包 optim,而不是 fitdistr。所以这是我的代码:

t1 <- sum(log(newdata$faminc)) 
t2 <- sum(newdata$faminc)
obs <- nrow(newdata)
lh.gamma <- function(par) {
  -((par[1]-1)*t1 - par[2]*t2 - obs*par[1]*log(par[2]) - obs*lgamma(par[1]))
}

#initial guess for a = mean^2(x)/var(x) and b = mean(x) / var(x) 
a1 <- (mean(newdata$faminc))^2/var(newdata$faminc)
b1 <- mean(newdata$faminc)/var(newdata$faminc)

init <- c(a1,b1)
q <- optim(init, lh.gamma, method = "BFGS")
q

还尝试在初始化向量中仅填充值,并包括这段代码;

  dlh.gamma <- function(par){
  cbind(obs*digamma(par[1])+obs*log(par[2])-t2,
     obs*par[1]/par[2]-1/par[2]^2*t1)
}

然后优化看起来像:

 q <- optim(init, lh.gamma, dhl.gamma, method="BFGS")

没有一个“有效”。首先,当我在学校计算机上尝试代码时,它为我提供了非常庞大的形状和速率参数数字,这是不可能的。现在,在家里尝试,我明白了:

> q <- optim(init, lh.gamma, method = "BFGS")
Error in optim(init, lh.gamma, method = "BFGS") : 
  non-finite finite-difference value [2]
In addition: There were 50 or more warnings (use warnings() to see the first 50)
> q
function (save = "default", status = 0, runLast = TRUE) 
.Internal(quit(save, status, runLast))
<bytecode: 0x000000000eaac960>
<environment: namespace:base>

q 甚至没有被“创建”。除了当我包含上面的 dlh.gamma 部分时,我只是再次得到大量数字并且没有收敛。

有谁知道出了什么问题/该怎么办?

编辑:

> dput(sample(newdata$faminc, 500))
c(42.5, 87.5, 22.5, 17.5, 12.5, 30, 30, 17.5, 42.5, 62.5, 62.5, 
30, 30, 150, 22.5, 30, 42.5, 30, 17.5, 8.75, 42.5, 42.5, 42.5, 
62.5, 42.5, 30, 17.5, 87.5, 62.5, 150, 42.5, 150, 42.5, 42.5, 
42.5, 6.25, 62.5, 87.5, 6.25, 87.5, 30, 150, 22.5, 62.5, 42.5,    
150, 17.5, 42.5, 42.5, 42.5, 62.5, 22.5, 42.5, 42.5, 30, 62.5, 
30, 62.5, 87.5, 87.5, 42.5, 22.5, 62.5, 22.5, 8.75, 30, 30, 17.5, 
87.5, 8.75, 62.5, 30, 17.5, 22.5, 62.5, 42.5, 30, 17.5, 62.5, 
8.75, 62.5, 42.5, 150, 30, 62.5, 87.5, 17.5, 62.5, 30, 62.5, 
87.5, 42.5, 62.5, 30, 62.5, 42.5, 87.5, 150, 12.5, 42.5, 62.5, 
42.5, 62.5, 62.5, 150, 30, 87.5, 12.5, 17.5, 42.5, 62.5, 30, 
6.25, 62.5, 42.5, 12.5, 62.5, 8.75, 17.5, 42.5, 62.5, 87.5, 8.75, 
62.5, 30, 62.5, 87.5, 42.5, 62.5, 62.5, 12.5, 150, 42.5, 62.5,  
12.5, 62.5, 42.5, 62.5, 62.5, 87.5, 42.5, 62.5, 30, 42.5, 150, 
42.5, 30, 62.5, 62.5, 87.5, 42.5, 30, 62.5, 62.5, 42.5, 42.5, 
30, 62.5, 42.5, 42.5, 62.5, 62.5, 150, 42.5, 30, 42.5, 62.5, 
17.5, 62.5, 17.5, 150, 8.75, 62.5, 30, 62.5, 42.5, 42.5, 22.5, 
150, 62.5, 42.5, 62.5, 62.5, 22.5, 30, 62.5, 30, 150, 42.5, 42.5, 
42.5, 62.5, 30, 12.5, 30, 150, 12.5, 8.75, 22.5, 30, 22.5, 30, 
42.5, 42.5, 42.5, 30, 12.5, 62.5, 42.5, 30, 22.5, 42.5, 87.5, 
22.5, 12.5, 42.5, 62.5, 62.5, 62.5, 30, 42.5, 30, 62.5, 30, 62.5, 
12.5, 22.5, 42.5, 22.5, 87.5, 30, 22.5, 17.5, 42.5, 62.5, 17.5, 
250, 150, 42.5, 30, 42.5, 30, 62.5, 17.5, 87.5, 22.5, 150, 62.5, 
42.5, 6.25, 87.5, 62.5, 42.5, 30, 42.5, 62.5, 42.5, 87.5, 62.5, 
150, 42.5, 30, 6.25, 22.5, 30, 42.5, 42.5, 62.5, 250, 8.75, 150, 
42.5, 30, 42.5, 30, 42.5, 42.5, 30, 30, 150, 22.5, 62.5, 30, 
8.75, 150, 62.5, 87.5, 150, 42.5, 30, 42.5, 42.5, 42.5, 30, 8.75, 
42.5, 42.5, 30, 22.5, 62.5, 17.5, 62.5, 62.5, 42.5, 8.75, 42.5, 
12.5, 12.5, 150, 42.5, 42.5, 17.5, 42.5, 62.5, 62.5, 42.5, 42.5, 
30, 42.5, 62.5, 30, 62.5, 42.5, 42.5, 42.5, 22.5, 62.5, 62.5, 
62.5, 22.5, 150, 62.5, 42.5, 62.5, 42.5, 30, 30, 62.5, 22.5, 
62.5, 87.5, 62.5, 42.5, 42.5, 22.5, 62.5, 62.5, 30, 42.5, 42.5, 
8.75, 87.5, 42.5, 42.5, 87.5, 30, 62.5, 17.5, 62.5, 42.5, 17.5, 
22.5, 62.5, 8.75, 62.5, 22.5, 22.5, 22.5, 42.5, 17.5, 22.5, 62.5, 
42.5, 42.5, 42.5, 42.5, 42.5, 30, 30, 8.75, 30, 42.5, 62.5, 22.5, 
6.25, 30, 42.5, 62.5, 17.5, 62.5, 42.5, 8.75, 22.5, 30, 17.5, 
22.5, 62.5, 42.5, 150, 87.5, 22.5, 12.5, 62.5, 62.5, 62.5, 30, 
42.5, 22.5, 62.5, 87.5, 30, 42.5, 62.5, 22.5, 87.5, 30, 30, 22.5, 
87.5, 87.5, 250, 30, 62.5, 250, 62.5, 42.5, 42.5, 62.5, 62.5, 
42.5, 6.25, 62.5, 62.5, 62.5, 42.5, 42.5, 150, 62.5, 62.5, 30, 
150, 22.5, 87.5, 30, 150, 17.5, 8.75, 62.5, 42.5, 62.5, 150, 
42.5, 22.5, 42.5, 42.5, 17.5, 62.5, 17.5, 62.5, 42.5, 150, 250, 
22.5, 42.5, 30, 62.5, 62.5, 42.5, 42.5, 30, 150, 150, 42.5, 17.5, 
17.5, 42.5, 8.75, 62.5, 42.5, 42.5, 22.5, 150, 62.5, 30, 250, 
62.5, 87.5, 62.5, 8.75, 62.5, 30, 30, 8.75, 17.5, 17.5, 150, 
22.5, 62.5, 62.5, 42.5)

faminc 变量在 1000s 以内

编辑2:

好的,代码很好,但现在我尝试使用以下方法拟合直方图上的分布:

x <- rgamma(500,shape=q$par[1],scale=q$par[2])
hist(newdata$faminc, prob = TRUE)
curve(dgamma(x, shape=q$par[1], scale=q$par[2]), add=TRUE, col='blue') 

它只是在 x 轴上产生一条蓝色的平线..

【问题讨论】:

  • 请在您的问题中包含dput(newdata$faminc)
  • 有 6547 个观测值..
  • 如果你暗示只知道观察次数就足以估计你的参数,那么我认为是时候再次打开你的统计教科书了......
  • 你想让我在这里包含 6547 个数字吗?我不明白。
  • 一个样本就足够了;也许dput(sample(newdata$faminc, 500)).

标签: r machine-learning gamma


【解决方案1】:

您有一些我无法解决的事情,但这里有一个估算的演示。

让我们从生成一些数据开始(这样我们就知道优化是否有效)。我只是在下面更改了您的优化函数,并使用了 Nelder-Mead 而不是准牛顿。

set.seed(23)
a <- 2 # shape
b <- 3 # rate

require(data.table)
newdata <- data.table(faminc = rgamma(10000, a, b))

t1 <- sum(log(newdata$faminc)) 
t2 <- sum(newdata$faminc)
obs <- nrow(newdata)

llf <- function(x){
  a <- x[1]
  b <- x[2]
  # log-likelihood function
  return( - ((a - 1) * t1 - b * t2 - obs * a * log(1/b) - obs * log(gamma(a))))
}

# initial guess for a = mean^2(x)/var(x) and b = mean(x) / var(x) 
a1 <- (mean(newdata$faminc))^2/var(newdata$faminc)
b1 <- mean(newdata$faminc)/var(newdata$faminc)

q <- optim(c(a1, b1), llf)
q$par
[1] 2.024353 3.019376

我想说我们已经很接近了。

使用您的数据:

(est <- q$par)
[1] 2.21333613 0.04243384

theoretical <- data.table(true = rgamma(10000, est[1], est[2]))
library(ggplot2)
ggplot(newdata, aes(x = faminc)) + geom_density() + geom_density(data = theoretical, aes(x = true, colour = "red")) + theme(legend.position = "none")

不是很好,但对于 500 obs 来说是合理的。

对 OP 编辑​​ 2 的回应:

您应该更仔细地查看您正在使用的函数,curve 接受函数参数,而不是向量值:

gamma_density = function(x, a, b) ((b^a)/gamma(a)) * (x^(a - 1)) * exp(-b * x)
hist(newdata$faminc, prob = TRUE, ylim = c(0, 0.015))
curve(gamma_density(x, a = q$par[1], b = q$par[2]), add=TRUE, col='blue')

【讨论】:

  • 非常感谢!我将进一步研究这个并自己尝试一下,并尝试它是否符合直方图的预期
  • 你是个英雄。非常感谢你。我仍在努力理解它,但我认为我会到达那里
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