R中的Data.frame：两列的连接，数字而不是出现答案

【问题标题】：Data.frame in R: concatenation of two column, numbers instead of occurrencesR中的Data.frame：两列的连接，数字而不是出现
【发布时间】：2016-11-08 11:33:08
【问题描述】：

我有一个非常简单的问题，但我找不到答案：我有这个 data.frame：

b=c("a","a","a","a","a","b","b","b","b","c")
c=c("b","b","b","b","b","c","c","c","c","d")

a<-data.frame(b,c)

如果我想将a$b 和a$c 向量放在一列中：

f<-c(a$b,a$c)

结果不一样

> f<-c(b,c)
> f
 [1] "a" "a" "a" "a" "a" "b" "b" "b" "b" "c" "b" "b" "b" "b" "b" "c" "c" "c" "c" "d"

但是

> f<-c(a$b,a$c)
> f
 [1] 1 1 1 1 1 2 2 2 2 3 1 1 1 1 1 2 2 2 2 3

？提前致谢！

编辑：试过这个，看看上面可能的重复建议：

> a<-data.frame(z=as.character(b),k=as.character(c))
> f<-c(a$z,a$k)
> f  [1] 1 1 1 1 1 2 2 2 2 3 1 1 1 1 1 2 2 2 2 3

【问题讨论】：

Convert data.frame columns from factors to characters的可能重复
你好，如果我没记错那不行，但是下yes的解决方法！
基本上，这是一个非常常见的问题，我们将因子视为字符并尝试对它们进行不同的操作。如果您这样做f <- c(as.character(a$z), as.character(a$k))，它也会起作用

标签： r dataframe data-manipulation

【解决方案1】：

您必须在data.frame() 函数中将stringsAsFactors 设置为FALSE。否则，字符串将被解释为因子，从而导致您不希望的输出。

b <- c("a","a","a","a","a","b","b","b","b","c")
c <- c("b","b","b","b","b","c","c","c","c","d")

a <- data.frame(b,c, stringsAsFactors = F)

f <- c(a$b,a$c)

f
[1] "a" "a" "a" "a" "a" "b" "b" "b" "b" "c" "b" "b" "b" "b" "b" "c" "c" "c" "c" "d"

【讨论】：