这个合并操作有什么问题？

Question

我正在 Oracle 11g 中执行 MERGE 操作，但它们返回的行数比预期的要多。

create table sales(product varchar2(20),month date, amount number(10))
insert into sales values('LG','01-Jan-17',20000);
insert into sales values('sony','01-Jan-18',22000);
insert into sales values('panasonic', '22-dec-17',18000);

create table sales_history(product varchar2(20),month date, amount number(10)) 
insert into sales_history values('sony', '22-dec-17',24000);
insert into sales_history values('panasonic', '22-dec-17',18000);

select * from sales;
select * from sales_history

merge into sales_history sh using(select product,month,amount from sales)s 
on (s.product=sh.product) 
when matched then update set sh.month=s.month,sh.amount=s.amount 
when not matched then insert(sh.product,sh.month,sh.amount)
values(s.product,s.month,s.amount);

我尝试在 Pl/SQL 中执行相同的查询，这将给我相同的结果，但它返回的行更多是重复的行。为什么会这样？

set serveroutput on
declare
s_product varchar2(20);
s_month date; 
s_amount number(10);
p_product s_product%type;
m_month s_month%type;
a_amount s_amount%type;

cursor sc1 is 
select product,month,amount from sales;
cursor shc2 is 
select product,month,amount from sales_history;

begin
open sc1;
open shc2;
loop <<l1>>
fetch sc1 into s_product,s_month,s_amount;
fetch shc2 into p_product,m_month,a_amount;
if s_product = p_product then
  if s_month <> m_month then
  update sales_history set month = s_month where product = s_product;
  end if;
  if s_amount <> a_amount then
  update sales_history set amount = s_amount where product = s_product;
  end if;
else
  INSERT INTO  sales_history(product, month, amount)
  SELECT product, month, amount FROM sales;
  dbms_output.put_line('DATA IS UPDATED');
end if;
exit when sc1%notfound;
exit when shc2%notfound;
end loop l1;
close sc1;
close shc2;
end;

select * from sales_history

Answer 1

我已经尝试在 oracle 12c 中执行上述案例并且它正在工作。请参阅下面提到的输出

 [SQL]create table sales(product varchar2(20),month date, amount number(10))
    Affected rows: 0
    Time: 0.012s

[SQL]insert into sales values('LG','01-Jan-17',20000)
Affected rows: 1
Time: 0.003s

[SQL]insert into sales values('sony','01-Jan-18',22000)
Affected rows: 1
Time: 0.004s

[SQL]insert into sales values('panasonic', '22-dec-17',18000)
Affected rows: 1
Time: 0.003s

[SQL]create table sales_history(product varchar2(20),month date, amount number(10))
Affected rows: 0
Time: 0.004s

[SQL]insert into sales_history values('sony', '22-dec-17',24000)
Affected rows: 1
Time: 0.002s

[SQL]insert into sales_history values('panasonic', '22-dec-17',18000)
Affected rows: 1
Time: 0.003s

[SQL]merge into sales_history sh using(select product,month,amount from sales)s 
on (s.product=sh.product) 
when matched then update set sh.month=s.month,sh.amount=s.amount 
when not matched then insert(sh.product,sh.month,sh.amount)
values(s.product,s.month,s.amount)
Affected rows: 3
Time: 0.015s

Answer 2

当你写作时 如果 s_product = p_product 那么 别的

当第一个产品名称是表sales中的sony时，它确实与sales_history中的sony匹配并给出期望输出，但它也与sales_hist中的其他条目不匹配并执行插入的代码的else部分，这给出结果是多行。 请参阅下面的输出，我尝试使用多个 dbms 输出。当索尼松下等时，其他部分正在执行。

set serveroutput on
declare
s_product varchar2(20);
s_month date; 
s_amount number(10);
p_product s_product%type;
m_month s_month%type;
a_amount s_amount%type;

cursor sc1 is 
select product,month,amount from sales;
cursor shc2 is 
select product,month,amount from sales_history;

begin
open sc1;
open shc2;
loop <<ll>>
fetch sc1 into s_product,s_month,s_amount;
fetch shc2 into p_product,m_month,a_amount;
dbms_output.put_line('outside if');
dbms_output.put_line(s_product);
dbms_output.put_line(p_product);
if s_product = p_product then
  dbms_output.put_line(p_product);
  if s_month <> m_month then
  dbms_output.put_line(m_month);
  update sales_history set month = s_month where product = s_product;
  end if;
  if s_amount <> a_amount then
  update sales_history set amount = s_amount where product = s_product;
  end if;
else
  INSERT INTO  sales_history(product, month, amount)
  SELECT product, month, amount FROM sales;
  dbms_output.put_line('DATA IS UPDATED');
end if;
exit when sc1%notfound;
exit when shc2%notfound;
end loop l1;
close sc1;
close shc2;
end;

 Output
outside if
LG
sony
DATA IS UPDATED
outside if
sony
panasonic
DATA IS UPDATED
outside if
panasonic
panasonic
panasonic