在 VBA Access 中用 null 替换撇号答案

【问题标题】：replace apostrophe with null in VBA Access在 VBA Access 中用 null 替换撇号
【发布时间】：2016-05-24 20:45:11
【问题描述】：

我正在尝试更新 Access 表中将撇号替换为 null 的字段。

Dim strLimitRecordTable As String: strLimitRecordTable = Me.txtLimitRecordTable
DoCmd.RunSQL "UPDATE " & strLimitRecordTable & " SET vCompanyMapped = replace(vCompanyMapped, ''', '') WHERE vCompanyMapped like '*'*';"

但我得到这个错误：

表达式替换中的语法错误(vCompanyMapped, ''', '') WHERE vCompanyMapped like ''';"

我觉得这与用空字符串''替换'''有关

我在这里做错了什么？

我有另一个可以正常工作的查询：

DoCmd.RunSQL "UPDATE [" & strLimitRecordTable & "] SET Domain = Mid([Email],InStr([Email],'@')+1,Len([Email])-InStr([Email],'@')) WHERE Email Like '*@*.*';"

【问题讨论】：

您在两个地方有语法错误。首先将 {like ' * ' * ';"} 更改为 {like '*';"} 然后将 {'''} 替换为 {"'"} [必须编辑，因为翻译了您的字符串而不是您所显示的]
@WayneG.Dunn 我尝试将 {'''} 替换为 {"'"} 但 VBA 将第一个引号视为语句的结尾，并将撇号视为注释的开头跨度>
@WayneG.Dunn 关于 {like '*';"} - 我这样做是因为我想确保该字段包含撇号。现在我想到了，我甚至不需要那个 WHERE 子句
是的，嵌入的引号可能会很麻烦...这是正确的语法：“UPDATE” & strLimitRecordTable &“ SET vCompanyMapped = Replace(vCompanyMapped, ""'"", """" ) WHERE ((vCompanyMapped Like ""'""));"但是，是的，我会摆脱 WHERE 子句...

标签： ms-access vba

【解决方案1】：

在这种情况下，我会使用 ascii 字符来查找撇号，我建议您尝试一下：

Dim strLimitRecordTable As String: strLimitRecordTable = 
Me.txtLimitRecordTable DoCmd.RunSQL "UPDATE " & strLimitRecordTable & " SET 
vCompanyMapped = replace(vCompanyMapped, chr(39),'') 
WHERE vCompanyMapped like '*'*';"

通常当我必须以编程方式搜索标点符号时，我发现使用 Ascii 指示符很有帮助。它有助于减少错误。

【讨论】：

谢谢，这很有用！我只需要在你的 replace() 中添加一个参数：replace(vCompanyMapped,Chr(39), '') 如上所述，我什至不需要导致语法错误的 WHERE 子句。
如果你能推荐我的修改答案，那么我会得到加分:)。

【解决方案2】：

在连接 SQL 时，您可以使用此功能来避免此问题和大多数其他问题：

' Converts a value of any type to its string representation.
' The function can be concatenated into an SQL expression as is
' without any delimiters or leading/trailing white-space.
'
' Examples:
'   SQL = "Select * From TableTest Where [Amount]>" & CSql(12.5) & "And [DueDate]<" & CSql(Date) & ""
'   SQL -> Select * From TableTest Where [Amount]> 12.5 And [DueDate]< #2016/01/30 00:00:00#
'
'   SQL = "Insert Into TableTest ( [Street] ) Values (" & CSql(" ") & ")"
'   SQL -> Insert Into TableTest ( [Street] ) Values ( Null )
'
' Trims text variables for leading/trailing Space and secures single quotes.
' Replaces zero length strings with Null.
' Formats date/time variables as safe string expressions.
' Uses Str to format decimal values to string expressions.
' Returns Null for values that cannot be expressed with a string expression.
'
' 2016-01-30. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function CSql( _
    ByVal Value As Variant) _
    As String

    Const vbLongLong    As Integer = 20
    Const SqlNull       As String = " Null"

    Dim Sql             As String
    Dim LongLong        As Integer

    #If Win32 Then
        LongLong = vbLongLong
    #End If
    #If Win64 Then
        LongLong = VBA.vbLongLong
    #End If

    Select Case VarType(Value)
        Case vbEmpty            '    0  Empty (uninitialized).
            Sql = SqlNull
        Case vbNull             '    1  Null (no valid data).
            Sql = SqlNull
        Case vbInteger          '    2  Integer.
            Sql = Str(Value)
        Case vbLong             '    3  Long integer.
            Sql = Str(Value)
        Case vbSingle           '    4  Single-precision floating-point number.
            Sql = Str(Value)
        Case vbDouble           '    5  Double-precision floating-point number.
            Sql = Str(Value)
        Case vbCurrency         '    6  Currency.
            Sql = Str(Value)
        Case vbDate             '    7  Date.
            Sql = Format(Value, " \#yyyy\/mm\/dd hh\:nn\:ss\#")
        Case vbString           '    8  String.
            Sql = Replace(Trim(Value), "'", "''")
            If Sql = "" Then
                Sql = SqlNull
            Else
                Sql = " '" & Sql & "'"
            End If
        Case vbObject           '    9  Object.
            Sql = SqlNull
        Case vbError            '   10  Error.
            Sql = SqlNull
        Case vbBoolean          '   11  Boolean.
            Sql = Str(Abs(Value))
        Case vbVariant          '   12  Variant (used only with arrays of variants).
            Sql = SqlNull
        Case vbDataObject       '   13  A data access object.
            Sql = SqlNull
        Case vbDecimal          '   14  Decimal.
            Sql = Str(Value)
        Case vbByte             '   17  Byte.
            Sql = Str(Value)
        Case LongLong           '   20  LongLong integer (Valid on 64-bit platforms only).
            Sql = Str(Value)
        Case vbUserDefinedType  '   36  Variants that contain user-defined types.
            Sql = SqlNull
        Case vbArray            ' 8192  Array.
            Sql = SqlNull
        Case Else               '       Should not happen.
            Sql = SqlNull
    End Select

    CSql = Sql & " "

End Function

【讨论】：