在 Oracle 中使用 connect by 在 with 子句中访问子查询中的父别名

Question

我正在尝试使用 connect by 递归获取一些数据，对于每一行，我需要知道不同树中是否包含特定项目。

所以我有这个 [精简] 查询：

select m.id, m.name,
   (select (
    with recursiveMetaClass as (
            select mb.name
            from meta mb
            start with mb.id = m.id
            connect by prior mb.metaclass = mb.id and mb.metaclass <> mb.id
    ) select name from recursiveMetaClass where name in ('config_group', 'config_item')
   ) from dual) as basetype
from meta m
inner join meta_rel mr on mr.rel2 = m.id
start with m.name = 'store_sys'
connect by prior m.id = mr.rel1
order siblings by item_order;

虽然 ORA-00904 "M"."ID": 在我的嵌套查询中开头的 m.id 上的标识符无效，但此错误。如果我将查询替换为：

select m.id, m.name,
   (select (
    with recursiveMetaClass as (
            select mb.name
            from meta mb
            start with mb.id = 1004
            connect by prior mb.metaclass = mb.id and mb.metaclass <> mb.id
    ) select name from recursiveMetaClass where name in ('config_group', 'config_item')
   ) from dual) as basetype
from meta m
inner join meta_rel mr on mr.rel2 = m.id
start with m.name = 'store_sys'
connect by prior m.id = mr.rel1
order siblings by item_order;

它有效（只是给出错误的结果）。

我怎样才能让 m.id 开始使用，或者重构它以使其工作？我还尝试使用一些嵌套选择并按级别 desc 执行 where on rownumber = 1 order，但是在尝试引用 m.id 时出现完全相同的错误。

谢谢！

Answer 1

您不能将此查询简化为以下内容吗？

select m.id, m.name, 
(      select mb.name  
       from meta mb 
       where name in ('config_group', 'config_item') 
       start with mb.id = m.id 
       connect by prior mb.metaclass = mb.id and mb.metaclass <> mb.id 
) as basetype
from meta m  
inner join meta_rel mr on mr.rel2 = m.id 
start with m.name = 'store_sys' 
connect by prior m.id = mr.rel1 
order siblings by item_order;