Clickhouse - 矩阵逐项加法：如何对二维数组求和？

Question

使用 Clickhouse 数据库计算表中矩阵的逐项总和的正确和最快的方法是什么？

我找到了这样的解决方案。但在我看来，这还不够理想。 还有一个，我需要为一维的每个元素指定 sumForEach()。

select array(sumForEach(matrix[1]), sumForEach(matrix[2])) from (
 select 1 as id, [[1,3], [2,4]] as matrix
 union all
 select 2 as id, [[2,4], [3,5]] as matrix
 union all
 select 3 as id, [[1,2], [1,0]] as matrix
)

因此，我希望看到一行带有结果矩阵

┌─m─────────────┐
│[[4,9],[6,9]]  │
└───────────────┘

Answer 1

Aggregate function combinators可以多次使用，有助于简化查询：

SELECT sumForEachForEach(matrix)
FROM 
(
    SELECT 
        1 AS id, 
        [[1, 3], [2, 4]] AS matrix
    UNION ALL
    SELECT 
        2 AS id, 
        [[2, 4], [3, 5]] AS matrix
    UNION ALL
    SELECT 
        3 AS id, 
        [[1, 2], [1, 0]] AS matrix
)
/*
┌─sumForEachForEach(matrix)─┐
│ [[4,9],[6,9]]             │
└───────────────────────────┘
*/