MySQL 基于得分和时间的排名

Question

我有两个 MySQL 表如下

表格：分数

表：用户

我的要求是对分数进行排名并在总分数大于某个值时检索（例如，如果总分数小于 15，则对所有分数进行排名）。如果分数相等，那么也要考虑时间。

我编写了以下查询来获取包括排名在内的行（我对 SQL 查询不太熟悉，但我试图找到一种方法来做到这一点 - 不走运）。

尝试 - 1

SELECT score.total_score,
       CONCAT(users.user_first_name,' ', users.user_last_name) AS name,
       users.user_email,
       FIND_IN_SET(total_score,
                     (SELECT GROUP_CONCAT(total_score
                                          ORDER BY total_score ASC)
                      FROM score)) AS rank
FROM score
INNER JOIN users ON score.user_id = users.user_id
WHERE score.total_score > 15
ORDER BY score.total_score DESC LIMIT 10

尝试 - 2

SET @Rank := 0;
SELECT score.total_score,score.time,
       CONCAT(users.user_first_name,' ', users.user_last_name) AS name,
       users.user_email,
       @Rank := @Rank + 1 AS rank
FROM score
INNER JOIN users ON score.score_id = users.user_id
WHERE score.total_score > 15
ORDER BY score.total_score DESC, time ASC LIMIT 10

两次尝试都失败了，总之我尝试做的是，

考虑时间，根据total_score对用户分数进行排名（有机会获得相同的分数）。

提前致谢。

Answer 1

你可以试试这个。 ORDER BY (score.total_score/score.time)

SET @Rank := 0;
SELECT score.total_score, score.time,
       CONCAT(users.user_first_name,' ', users.user_last_name) AS name,
       users.user_email,
       (@Rank := @Rank + 1) AS rank
FROM score
INNER JOIN users ON score.user_id = users.user_id
WHERE score.total_score > 15
ORDER BY (score.total_score/score.time) ASC LIMIT 10