【问题标题】:Creating a download for zip file containing text/csv from string variables从字符串变量创建包含文本/csv 的 zip 文件的下载
【发布时间】:2017-11-22 05:32:36
【问题描述】:

我目前需要创建一个 zip 文件以供下载。这应该包含两 (2) 个要从字符串变量创建的 csv 文件。我不知道该怎么做。我的草稿在下面。

public @ResponseBody Object getFileV1(HttpServletRequest request, HttpServletResponse response) {
  try {
        response.setContentType("application/zip");
        response.setHeader("Content-Disposition", "attachment; filename=Reassigned Tickets Report " + new Date().toString()  + ".zip");
        String stringValue1 = "This is a test value for csv1";
        String stringValue2 = "This is a test value for csv2";
        InputStream is1 = new ByteArrayInputStream(stringValue1.getBytes("UTF-8"));
        InputStream is2 = new ByteArrayInputStream(stringValue2.getBytes("UTF-8"));
        ZipInputStream zin;
        ZipEntry entry;
        ZipOutputStream zout= new ZipOutputStream(response.getOutputStream());

        zin = new ZipInputStream(is1);
        entry = zin.getNextEntry();
        zout.putNextEntry(entry); 

        zin = new ZipInputStream(is2);
        entry = zin.getNextEntry();
        zout.putNextEntry(entry); 

        zout.closeEntry();
        zin.close();
        zout.close();

        response.flushBuffer();
        return null;

    } catch (Exception e) {
        e.printStackTrace();
        return e;
    }
}

显然这是行不通的。可能是因为我还是个新手。请多多包涵。

我在调用“zout.putNextEntry”的那一行得到一个“java.lang.NullPointerException”。非常感谢您的建议。提前谢谢你。

【问题讨论】:

    标签: java spring-mvc httpresponse zipfile download


    【解决方案1】:

    经过一天的环顾,我解决了我的问题。这对我有用。但我不确定这是否是最有效的方法。

        public @ResponseBody Object getFileV1(HttpServletRequest request, HttpServletResponse response) {
            try {
                response.setContentType("application/zip");
                response.setHeader("Content-Disposition", "attachment; filename=Test Report " + new Date().toString()  + ".zip");
                String stringValue1 = "This is a test value for csv1";
                String stringValue2 = "This is a test value for csv2";
    
                PrintWriter writer1 = new PrintWriter(new OutputStreamWriter(new FileOutputStream("stringValue1.csv"), "UTF-8"));
                writer1.print(stringValue1);
                writer1.close();
    
                PrintWriter writer2 = new PrintWriter(new OutputStreamWriter(new FileOutputStream("stringValue2.csv"), "UTF-8"));
                writer2.print(stringValue2);
                writer2.close();
    
    
                File file1 = new File("stringValue1.csv");
                File file2 = new File("stringValue2.csv");
                filesToZip(response, file1, file2);     
    
                file1.delete();
                file2.delete();
    
                response.flushBuffer();
                return null;
    
            } catch (Exception e) {
                e.printStackTrace();
                return e;
            }
        }
    

    这是我从另一个线程得到的方法,经过一些修改。

        public static void filesToZip(HttpServletResponse response, File... files) throws IOException {
            // Create a buffer for reading the files
            byte[] buf = new byte[1024];
            // create the ZIP file
            ZipOutputStream out = new ZipOutputStream(response.getOutputStream());
            // compress the files
            for(int i=0; i<files.length; i++) {
                FileInputStream in = new FileInputStream(files[i].getName());
                // add ZIP entry to output stream
                out.putNextEntry(new ZipEntry(files[i].getName()));
                // transfer bytes from the file to the ZIP file
                int len;
                while((len = in.read(buf)) > 0) {
                    out.write(buf, 0, len);
                }
                // complete the entry
                out.closeEntry();
                in.close();
            }
            // complete the ZIP file
            out.close();
        }
    

    我唯一不喜欢的是我必须创建临时文件并在处理后删除它们。

    【讨论】:

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