创建包含变量名作为字符串加值的 txt 文件

Question

我想创建一个包含给定变量列表的文件，例如：

a1 = 3
a2 = 3
a3 = 4
a4 = 6
a5 = 'test'
a6 = 19
a7 = 19

输出应该如下所示：

test.txt

a1 = 3
a2 = 3
a3 = 4
a4 = 6
a5 = 'test'
a6 = 19
a7 = 19

txt 文件的内容。

建立模型时需要它。

我试过这样：

def namestr(obj, namespace):
    names = [name for name in namespace if namespace[name] is obj]
    name = [n for n in names if 'a' in n]
    return name[0]

with open("setupfile.txt", "w") as setupfile:
    x = [a1, a2, a3, a4, a5, a6, a7]
    for name in x:
        print(name)
        setupfile.write(namestr(name, globals()) + "=" + repr(name) +"\n")
        print(repr(name))
    setupfile.close()

但这不是一个充分的解决方案。具有相同值的变量在文本文件中具有相同的名称。

是否有更好的解决方案来创建所描述的文本文件？也许是获取变量名称的更好方法。

Answer 1

我也遇到了同样的问题。如果它适合您，您可能应该尝试这种方式。

class NewClass(object): pass

names = NewClass()
vars = ['a1', 'a2', 'a3','a4','a5','a6','a7']

for v in vars: 
    setattr(names, v, eval(v)) 


with open("setupfile.txt","w") as setupfile:
    members = [attr for attr in dir(names) if not callable(getattr(names, attr)) and not attr.startswith("__")]

    for i in range(0,len(members)):
        #print(name)
        setupfile.write(members[i] + '=' + str(getattr(names, members[i])) + "\n")
        #print(repr(name))
setupfile.close()`