【发布时间】:2018-06-04 02:14:40
【问题描述】:
我使用倒置锁作为信号量来表示队列更新(注意注释掉的Sleep(1),稍后会用到):
#include <stdio.h>
#include <omp.h>
#include <queue>
#include <stdint.h>
#include <windows.h>
class ThreadLock
{
protected:
omp_lock_t lock;
public:
ThreadLock() {
omp_init_lock(&lock);
}
~ThreadLock() {
omp_destroy_lock(&lock);
}
void acquire() {
omp_set_lock(&lock);
}
void release() {
omp_unset_lock(&lock);
}
};
std::queue< uint32_t > g_queue;
ThreadLock g_lock;
void producer()
{
uint32_t seq = 0;
g_lock.acquire();
while (true) {
Sleep(200);
#pragma omp critical
g_queue.push(++seq);
printf("Produced %u\n", seq);
g_lock.release();
//Sleep(1);
g_lock.acquire();
}
g_lock.release();
}
void consumer()
{
while (true) {
// Lock if empty
if (g_queue.empty()) {
printf("[Consumer] Acquiring lock\n");
g_lock.acquire();
g_lock.release();
printf("[Consumer] Released lock\n");
if (g_queue.empty()) {
printf("Still empty\n");
Sleep(100);
continue;
}
}
#pragma omp critical
{
printf("Consumed %u\n", g_queue.front());
g_queue.pop();
}
}
}
int main(int argc, char* argv[])
{
#pragma omp parallel sections
{
#pragma omp section
consumer();
#pragma omp section
producer();
}
return 0;
}
此代码包含一个竞争条件,它会在一段时间后使消费者停止,如下所示:
[Consumer] Acquiring lock
Produced 1
Produced 2
[Consumer] Released lock
Consumed 1
Consumed 2
[Consumer] Acquiring lock
Produced 3
Produced 4
Produced 5
Produced 6
Produced 7
Produced 8
Produced 9
Produced 10
Produced 11
Produced 12
Produced 13
Produced 14
Produced 15
Produced 16
Produced 17
Produced 18
Produced 19
似乎生产者线程在没有上下文切换的情况下匆忙通过释放/获取。美好的。让我们通过取消注释 Sleep(1) 来强制它:
[Consumer] Acquiring lock
Produced 1
[Consumer] Released lock
Consumed 1
[Consumer] Acquiring lock
[Consumer] Released lock
Still empty
[Consumer] Acquiring lock
Produced 2
[Consumer] Released lock
Consumed 2
[Consumer] Acquiring lock
[Consumer] Released lock
Still empty
[Consumer] Acquiring lock
Produced 3
[Consumer] Released lock
Consumed 3
注意到那些Still empty 行了吗?看起来消费者设法在生产者的发布/获取行之间进行了额外的处理。
我知道在消费者线程中添加另一个 Sleep(1) 可以解决问题。但是我觉得代码中这些固定的人为延迟是错误的(Sleep(200) 不算,它仅用于演示目的)。
如何正确地使用 OpenMP 和不使用高于 2.0 的 OpenMP 版本?
【问题讨论】:
-
我并没有真正遵循您的代码,在您的示例中,生产和消费的实际代码应该放在哪里?
标签: c++ multithreading synchronization openmp race-condition