【发布时间】:2018-07-20 16:39:57
【问题描述】:
当我使用invokeMethod 发送方法调用时,如果发送代码等待调用,但目标对象随后死亡,会发生什么情况?这会以无限的等待结束吗?或者 Qt 会唤醒调用者并返回 false(这将是一种未记录的行为,我自己最好的猜测)?
【问题讨论】:
标签: c++ qt conditional-statements semaphore signals-slots
当我使用invokeMethod 发送方法调用时,如果发送代码等待调用,但目标对象随后死亡,会发生什么情况?这会以无限的等待结束吗?或者 Qt 会唤醒调用者并返回 false(这将是一种未记录的行为,我自己最好的猜测)?
【问题讨论】:
标签: c++ qt conditional-statements semaphore signals-slots
以下示例在invokeMethod 等待BlockingQueuedConnection 时删除工作对象:
#include <QtCore>
//a thread that can be destroyed at any time
//see http://stackoverflow.com/a/25230470
class SafeThread : public QThread{
using QThread::run;
public:
explicit SafeThread(QObject* parent= nullptr):QThread(parent){}
~SafeThread(){ quit(); wait(); }
};
//The function queues a functor to get executed in a specified worker's thread
template <typename Func>
void PostToThread(QThread* thread, Func&& f) {
//see http://stackoverflow.com/a/21653558
QObject temporaryObject;
QObject::connect(&temporaryObject, &QObject::destroyed,
thread->eventDispatcher(), std::forward<Func>(f),
Qt::QueuedConnection);
}
//a typical QObject worker that can "printName"
class Worker : public QObject {
Q_OBJECT
public:
using QObject::QObject;
~Worker() {
qInfo() << "destroying " << objectName()
<< " in " << QThread::currentThread()->objectName();
}
Q_SLOT void printName() {
qInfo() << "my name is " << objectName()
<< " in " << QThread::currentThread()->objectName();
}
};
int main(int argc, char *argv[]) {
QCoreApplication a(argc, argv);
//create worker
Worker *worker = new Worker;
worker->setObjectName("worker");
//start worker thread and move worker to it
SafeThread t;
worker->moveToThread(&t);
t.start();
//set thread names (for better output)
QThread::currentThread()->setObjectName("main_thread");
t.setObjectName("worker_thread");
//normal QMetaObject::invokeMethod usage
if(QMetaObject::invokeMethod(worker, "printName",
Qt::BlockingQueuedConnection)) {
qInfo() << "printName called successfully before deletion";
}
//the lambda function will be executed in the worker thread
PostToThread(&t, [worker]{
qInfo() << "blocking " << QThread::currentThread()->objectName();
QThread::sleep(2); //block worker thread for 2 seconds
delete worker; //delete worker
});
//at this point the worker thread is about to destroy the worker object (but
//hasn't done so yet)
if(QMetaObject::invokeMethod(worker, "printName",
Qt::BlockingQueuedConnection)) {
qInfo() << "printName called successfully after deletion!";
}
QTimer::singleShot(100, &a, &QCoreApplication::quit);
return a.exec();
}
#include "main.moc"
输出(在 Qt 5.9.1、Qt 5.7 - windows、debian 上测试):
my name is "worker" in "worker_thread"
printName called successfully before deletion
blocking "worker_thread"
destroying "worker" in "worker_thread"
printName called successfully after deletion!
所以一个简短的答案是:invokeMethod 返回true,但没有被调用。但是,请注意,您必须保证worker对象在开头仍然有效(更多详细信息请参见最后一点)invokeMethod调用主线程(否则为UB) .
这是我通过挖掘 Qt 的代码得出的一系列结论:
ivokeMethod 仅在传递给它的参数有问题时才返回 false(例如,槽签名与参数计数/类型不匹配、返回类型不匹配、未知连接类型……)。见here。Qt::BlockingQueuedConnection时,invokeMethod会被acquiring a QSemaphore阻塞调用线程。 QSemaphore 存储在QMetaCallEvent 中,该QMetaCallEvent 发布到接收器对象。QSemaphoreis releasedQMetaCallEvent被销毁时。QObject 的析构函数负责调用QCoreApplication::removePostedEvents() 来为被析构的对象。这意味着事件队列中针对一个对象的所有事件都会在该对象被销毁时被销毁。见here。invokeMethod 时保持活动状态,直到获得提到的信号量,因为invokeMethod 可能会在任何时候尝试访问工作对象。我认为这一要求在实践中会使事情变得复杂,因为最终可能不得不在整个 invokeMethod 调用中保证对象的生命周期(从而避免整个问题)。【讨论】: