【发布时间】:2013-12-03 08:35:42
【问题描述】:
我想在优先级队列中插入元素以便对它们进行排序,但我没有正确使用 min_heapify 函数。到目前为止,这是我的代码:-
#include <stdio.h>
#include <stdlib.h>
struct entity{ //An entity consists has its data and its priority
int data;
int priority;
};
void swap(int *a ,int *b){
int temp = *a; *a = *b; *b = temp;
}
void min_heapify(struct entity a[], int p){
int r = (p+1)*2, l=r-1, smallest = p; //p is parent, r is right child and l is left child
if(l < p && a[l].priority < a[p].priority) smallest = l;
if(r < p && a[r].priority < a[smallest].priority) smallest = r;
if(smallest != p){
swap(&a[p].data, &a[smallest].data); //swap child and parent if parent isn't the smallest
swap(&a[p].priority, &a[smallest].priority);
min_heapify(a, smallest); //Keep on calling same method until parent is the smallest
}
}
void display(struct entity a[], int count){
printf("The Queue is:-\n");
if(count == 0) printf("Empty.");
else for(int i = 0; i < count; i++)
printf("\n%d\t(priority: %d)\n", a[i].data, a[i].priority);
}
int main(){
int n, count = 0, choice;
printf("Enter the size of the priority queue: ");
scanf("%d", &n);
struct entity *a = (struct entity*)malloc(sizeof(struct entity) * n);
while(1){
display(a, count);
printf("1.Insert 2.Exit: ");
scanf("%d", &choice);
switch(choice){
case 1: if(count < n){
printf("\nEnter the number and its priority:-\n");
scanf("%d%d", &a[count].data, &a[count].priority);
min_heapify(a, (++count)/2);
}break;
case 2: return 0;
}
}
}
【问题讨论】:
-
您是否尝试过在调试器中逐行执行代码?如果没有,那就这样做吧,希望能帮助你缩小问题的范围。
标签: c logic heap runtime-error priority-queue