【发布时间】:2012-03-29 10:56:21
【问题描述】:
我尝试使用 sql.rows() Groovy 方法获取一些数据,但返回值需要很长时间。
所以我尝试了“标准”方式,它的速度要快得多(快 150 倍)。
我错过了什么?
看下面的代码:第一个方法在大约 2500 毫秒内返回结果,第二个在 15 毫秒内返回结果!
class MyService {
javax.sql.DataSource dataSource
def SQL_QUERY = "select M_FIRSTNAME as firstname, M_LASTNAME as lastname, M_NATIONALITY as country from CT_PLAYER order by M_ID asc";
def getPlayers1(int offset, int maxRows)
{
def t = System.currentTimeMillis()
def sql = new Sql(dataSource)
def rows = sql.rows(SQL_QUERY, offset, maxRows)
println "time1 : ${System.currentTimeMillis()-t}"
return rows
}
def getPlayers2(int offset, int maxRows)
{
def t = System.currentTimeMillis();
Connection connection = dataSource.getConnection();
Statement statement = connection.createStatement();
statement.setMaxRows(offset + maxRows -1);
ResultSet resultSet = statement.executeQuery(SQL_QUERY);
def l_list =[];
if(resultSet.absolute(offset)) {
while (true) {
l_list << [
'firstname':resultSet.getString('firstname'),
'lastname' :resultSet.getString('lastname'),
'country' :resultSet.getString('country')
];
if(!resultSet.next()) break;
}
}
resultSet.close()
statement.close()
connection.close()
println "time2 : ${System.currentTimeMillis()-t}"
return l_list
}
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