CUDA 无挥发性

Question

谁能给我建议一种在 CUDA 中释放易失性全局内存变量的方法...

volatile unsigned *d_queue_L12;
err = cudaMalloc((void **)&d_queue_L12, CORES*MAX_12*Cache_Sets_L2*sizeof(volatile unsigned));
if (err != cudaSuccess)
{
    fprintf(stderr, "Failed to allocate space to L12 QUEUE vector (error code %s)!\n",     cudaGetErrorString(err));
    exit(EXIT_FAILURE);
}

err = cudaFree(d_queue_L12);
if (err != cudaSuccess)
{
    fprintf(stderr, "Failed to free L2 FLAG COUNT vector (error code %s)!\n", cudaGetErrorString(err));
    exit(EXIT_FAILURE);
}

给出一个错误： 错误：“volatile unsigned int *”类型的参数与“void *”类型的参数不兼容

Answer 1

这样的事情怎么样：

err = cudaFree((void *)d_queue_L12);