Func<T,bool> 扩展条件

Question

我有一个接受Func<T,bool> 条件作为参数的方法，我想将条件扩展为：

public T SomeClass.GETConditionalValue(x=>x.Id==id).ToList();

现在这个SomeClass.GETConditionalValue 需要一个参数Func<T,bool> 条件 我想修改它而不打扰SomeClass.GETConditionalValue

类似这样的：

public T SomeClass.GETConditionalValue(ApplyFilter(x=>x.Id==id)).ToList();

在哪里

public Func<T,bool>ApplyFilter<T>(Func<T,bool>condition) where T: GenericCLass
{

   return condition (+ some new condition in & or || block) 
}

**UPDATE :- ** 不能在这里使用委托，抛出无法将 lemda 表达式转换为 bool 类型，因为它不是委托类型

   public IEnumerable<T> GetEntities<T>(Func<T, bool> condition) where T : ITableEntity, new()
        {
            if (applicationFilter == null)
                return tableContext.CreateQuery<T>().Where(condition).ToList();
            return tableContext.CreateQuery<T>().Where(applicationFilter).Where(condition).ToList();
        }
 

我的电话是

 var mappedApplications = userToMdouleRepo.GetEntities<UserMappingToModules>(x => x.UserEmail == email)

这里我想改一下

 var mappedApplications = userToMdouleRepo.GetEntities<UserMappingToModules>(ApplyAdditionalFilter(x => x.UserEmail == email)).ToList()

Answer 1

你可以这样做：

public Func<T, bool> ApplyFilter<T>(Func<T, bool> condition) where T: GenericClass
{
    return t => condition(t) (+ some new condition in & or || block) 
}

例如：

public class GenericClass
{
    public string Name { get; }
}

public Func<T, bool> ApplyFilter<T>(Func<T, bool> condition) where T: GenericClass
{
    return t => condition(t) && t.Name == "SomeName";
}