【发布时间】：2015-06-12 18:11:36
【问题描述】：
我用java做了一个井字游戏。我已经完成了代码，但我不确定如何检查对角线上是否有赢家。我试图输入的是：
win[x] += (board[0][2] + board[1][1] + board[2][0]);
x++;
win[x] += (board[0][0] + board[1][1] + board[2][2]);
但它似乎不起作用。非常感谢您对解决此问题的任何帮助！
井字游戏
import java.util.Scanner;
import java.util.Random;
public class TicTac
{
public static void main(String[]args)
{
Scanner reader = new Scanner(System.in);
TTTBoard board = new TTTBoard();
System.out.println(board);
Random gen = new Random();
char player;
if(gen.nextInt(2) == 1)
{
player = 'O';
}
else
{
player = 'X';
}
System.out.println("Would you like to play against the computer?");
String computer = reader.nextLine();
while(board.getWinner() == '-' && !board.full())
{
int row = 0;
int column = 0;
boolean success = false;
System.out.println(player + "'s turn.");
if(computer.equals("No")||player=='X')
{
System.out.print("Enter the row and column[1-3, space, 1-3]");
row = reader.nextInt();
column = reader.nextInt();
success = board.placeXorO(player, row, column);
}
else
{
while(!success)
{
row = gen.nextInt(3) +1;
column = gen.nextInt(3) +1;
success = board.placeXorO(player, row, column);
}
}
if(!success)
{
System.out.println("Error: cell already occupied");
}
else
{
System.out.println(board);
if(player == 'X')
{
player = 'O';
}
else
{
player = 'X';
}
}
}
char winner = board.getWinner();
if(winner != '-')
{
System.out.println(winner + "'s wins!");
}
else
{
System.out.println("It's a draw!");
}
}
}
TTTBoard 类
public class TTTBoard{
private char[][]board;
public TTTBoard()
{
board = new char[3][3];
reset();
}
public void reset()
{
for(int row = 0; row < 3; row++)
{
for(int col = 0; col < 3; col++)
{
board[row][col]= '-';
}
}
}
public String toString()
{
String result = "\n";
for(int row = 0; row < 3; row++)
{
for (int col = 0; col < 3; col++)
{
result += board[row][col] + " ";
}
result += "\n";
}
return result;
}
public boolean placeXorO(char player, int row, int col)
{
if(board[row-1][col-1]=='-')
{
board[row-1][col-1] = player;
return true;
}
else
{
return false;
}
}
public boolean full()
{
for(int row = 0; row < 3; row++)
{
for(int col = 0; col < 3; col++)
{
if(board[row][col] == '-')
{
return false;
}
}
}
return true;
}
public char getWinner()
{
String[]win = new String[8];
int x =0;
for(int y =0; y < 8; y++)
{
win[y] = "";
}
for(int row = 0; row <3; row++)
{
for (int col = 0; col < 3; col++)
{
win[x] += board[row][col];
}
x++;
}
for(int col = 0; col <3; col++)
{
for (int row = 0; row < 3; row++)
{
win[x] += board[row][col];
}
x++;
}
win[x] += (board[0][2] + board[1][1] + board[2][0]);
x++;
win[x] += (board[0][0] + board[1][1] + board[2][2]);
char winner = '-';
for(int i = 0; i < 8; i++)
{
if (win[i].equals("XXX"))
{
winner = 'X';
}
if(win[i].equals("OOO"))
{
winner = 'O';
}
}
return winner;
}
}
【问题讨论】：
标签： java tic-tac-toe