【问题标题】:Using R to find probability [closed]使用 R 求概率 [关闭]
【发布时间】:2020-10-10 17:48:59
【问题描述】:

a) 在一个 20 人的小组中,有 3 个姐妹。该组被分开在 随机分成两组,每组 10 个。姐妹们在 同一组? b) 编写 R 代码以使用仿真解决问题。

我在 B 部分有困难。我无法理解如何模拟这种情况

【问题讨论】:

    标签: r combinations probability


    【解决方案1】:

    这似乎有点像家庭作业转储 - 最好看到你付出一些努力,但你似乎不知道从哪里开始。

    我已注释以下代码以显示一种可能的方法

    # Make the sample reproducible
    set.seed(69)
    
    # Calculate the probability that the brothers will be in the same group
    prob_calculated <- 20/20 * 9/19 * 8/18
    
    # Create our sample space. Here, 1 stands for one of the brothers, 
    # a zero means a non-brother:
    space <- c(1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)
    
    # Create an empty vector to store the results of our simulation
    vec <- logical()
    
    # For 10,000 simulations, we will draw 10 numbers from space without replacement.
    # If the sum of the sample is three or zero, the brothers are all in the same group.
    # We store the result of each simulation in the vector vec at position i.
    for(i in 1:10000) {
      samp <- sample(space, 10)
      vec[i] <- sum(samp) == 0 | sum(samp) == 3
    }
    
    # The proportion of TRUE results in vec estmates the probability
    prob_simulated <- length(which(vec))/10000
    
    # Now we present the results for comparison
    c(prob_calculated = prob_calculated, prob_simulated = prob_simulated)
    #> prob_calculated  prob_simulated 
    #>       0.2105263       0.2149000
    

    reprex package (v0.3.0) 于 2020 年 10 月 10 日创建

    【讨论】:

      猜你喜欢
      • 2022-01-10
      • 2013-07-18
      • 2012-08-22
      • 1970-01-01
      • 1970-01-01
      • 1970-01-01
      • 1970-01-01
      • 1970-01-01
      • 2018-10-27
      相关资源
      最近更新 更多