【发布时间】:2017-07-23 16:18:09
【问题描述】:
root1
child1
child2
grandchild1
grandchild2
child3
root2
child1
child2
grandchild1
greatgrandchild1
我有一个像上面这样的树结构的对象数组,我想像这样获取所有唯一路径
Food->Dry Food Items->Local Dry Food Items
Food->Dry Food Items->Thai Dry Food Items
Food->Dry Food Items->Others
Food->Fruits
------
------
这是我的对象
[
{
"id": 1,
"name": "Food",
"parent_id": 0,
"children": [
{
"id": 5,
"name": "Dry Food Items",
"parent_id": 1,
"children": [
{
"id": 11,
"name": "Local Dry Food Items",
"parent_id": 5
},
{
"id": 12,
"name": "Thai Dry Food Items",
"parent_id": 5
},
{
"id": 60,
"name": "Others",
"parent_id": 5
}
]
},
{
"id": 6,
"name": "Fruits",
"parent_id": 1
},
{
"id": 7,
"name": "LG Branded",
"parent_id": 1
},
{
"id": 8,
"name": "Meat",
"parent_id": 1
},
{
"id": 9,
"name": "Sea food",
"parent_id": 1
},
{
"id": 10,
"name": "Vegetables",
"parent_id": 1,
"children": [
{
"id": 14,
"name": "Local Vegetables",
"parent_id": 10
},
{
"id": 15,
"name": "Thai Vegetables",
"parent_id": 10
}
]
},
{
"id": 38,
"name": "Frozen",
"parent_id": 1
},
{
"id": 39,
"name": "IP Kitchen",
"parent_id": 1,
"children": [
{
"id": 40,
"name": "IP Meat",
"parent_id": 39
},
{
"id": 41,
"name": "IP Starter",
"parent_id": 39
},
{
"id": 42,
"name": "IP Ingredients",
"parent_id": 39
},
{
"id": 43,
"name": "IP Sauce",
"parent_id": 39
},
{
"id": 44,
"name": "IP Seafood",
"parent_id": 39
},
{
"id": 45,
"name": "IP Starter",
"parent_id": 39
},
{
"id": 46,
"name": "IP Desert",
"parent_id": 39
}
]
}
]
},
{
"id": 2,
"name": "Beverage",
"parent_id": 0,
"children": [
{
"id": 16,
"name": "Bar",
"parent_id": 2
},
{
"id": 17,
"name": "Coffee & Tea",
"parent_id": 2
},
{
"id": 18,
"name": "In Can",
"parent_id": 2
},
{
"id": 19,
"name": "Water",
"parent_id": 2
},
{
"id": 47,
"name": "IP Bar",
"parent_id": 2
}
]
},
{
"id": 3,
"name": "Disposable",
"parent_id": 0,
"children": [
{
"id": 21,
"name": "Disposable",
"parent_id": 3
}
]
},
{
"id": 4,
"name": "SOE",
"parent_id": 0,
"children": [
{
"id": 20,
"name": "Cleaning Materials",
"parent_id": 4
},
{
"id": 22,
"name": "Chinaware",
"parent_id": 4
}
]
}
];
我到达树中的所有节点
function traverse(categories) {
categories.forEach(function (category) {
if (category.children && category.children.length) {
traverse(category.children);
}
else {
}
}, this);
}
【问题讨论】:
-
试过什么?
-
你想知道什么?是你尝试过的编程问题吗?
-
发布一个有效的对象。
标签: javascript angularjs tree