Unity 2D 中的口吃运动

Question

所以基本上我试图让玩家移动系统类似于 RPG Maker 中的一个具有 8 个方向的移动系统。不知何故，我成功了，但只是部分成功。当我试图突然改变前任的方向时。从上到左，角色口吃，不想在不先释放所有键的情况下移动。

重力比例被禁用或更像设置为0，身体类型是动态的。

这是一个代码：

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class MoveChar : MonoBehaviour {

Rigidbody2D rigid;

public float Speed;

// Use this for initialization
void Start () {

    rigid = GetComponent<Rigidbody2D>();

}

// Update is called once per frame
void Update () {

//        float horiz = Input.GetAxis("Horizontal");

//        float vert = Input.GetAxis("Vertical");

    if(Input.GetKeyDown(KeyCode.W)) //________________________________________MOVING UP

    {
        rigid.velocity = new Vector2(rigid.velocity.x, 1 * Speed);
    }
    else if(Input.GetKeyUp(KeyCode.W))
    {
        rigid.velocity = new Vector2(0, 0);
    }

    if (Input.GetKeyDown(KeyCode.S)) //_______________________________________MOVING DOWN
    {
        rigid.velocity = new Vector2(rigid.velocity.x, -1 * Speed);
    }
    else if (Input.GetKeyUp(KeyCode.S))
    {
        rigid.velocity = new Vector2(0, 0);
    }


    if (Input.GetKeyDown(KeyCode.A)) //_______________________________________MOVING LEFT
    {
        rigid.velocity = new Vector2(-1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.A))
    {
        rigid.velocity = new Vector2(0, 0);
    }

    if (Input.GetKeyDown(KeyCode.D)) //_______________________________________MOVING RIGHT
    {
        rigid.velocity = new Vector2(1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.D))
    {
        rigid.velocity = new Vector2(0, 0);
    }
}

Answer 1

使用Input.GetAxis(axisName) 来避免输入代码中的大小写冲突。此外，使用 AddForce 可以很好地与其他刚体配合使用。

Vector2 oldV = rigid.velocity;
float horiz = Input.GetAxis("Horizontal");
float vert = Input.GetAxis("Vertical");

Vector2 newV = new Vector2(horiz * Speed, vert * Speed);
rigid.AddForce(newV-oldV, ForceMode2D.Impulse);

或者，当键被抬起/按下时，跟踪你自己的轴

public float horiz;
public float vert;

void Start() {
    horiz = 0f;
    vert = 0f;
    if (Input.GetKey(KeyCode.A)) horiz -= 1f;
    if (Input.GetKey(KeyCode.D)) horiz += 1f;
    if (Input.GetKey(KeyCode.S)) vert -= 1f;
    if (Input.GetKey(KeyCode.W)) vert += 1f;
}

void Update () {
    Vector2 oldV = rigid.velocity;

    if(Input.GetKeyDown(KeyCode.W)) vert += 1f;
    else if(Input.GetKeyUp(KeyCode.W)) vert -= 1f;

    if (Input.GetKeyDown(KeyCode.S)) vert -= 1f;
    else if (Input.GetKeyUp(KeyCode.S)) vert += 1f;

    if (Input.GetKeyDown(KeyCode.A)) horiz -= 1f;
    else if (Input.GetKeyUp(KeyCode.A)) horiz += 1f;

    if (Input.GetKeyDown(KeyCode.D)) horiz += 1f;
    else if (Input.GetKeyUp(KeyCode.D)) horiz -= 1f;

    Vector2 newV = new Vector2(horiz * Speed, vert * Speed);
    rigid.AddForce(newV-oldV, ForceMode2D.Impulse);
}

Answer 2

释放按钮只有一个小问题。在不受键影响的方向上添加原力。整个脚本应该是这样的：

void Update()
{
    if (Input.GetKeyDown(KeyCode.W)) //________________________________________MOVING UP
    {
        rigid.velocity = new Vector2(rigid.velocity.x, 1 * Speed);
    }
    else if (Input.GetKeyUp(KeyCode.W))
    {
        rigid.velocity = new Vector2(rigid.velocity.x, 0);
    }

    if (Input.GetKeyDown(KeyCode.S)) //_______________________________________MOVING DOWN
    {
        rigid.velocity = new Vector2(rigid.velocity.x, -1 * Speed);
    }
    else if (Input.GetKeyUp(KeyCode.S))
    {
        rigid.velocity = new Vector2(rigid.velocity.x, 0);
    }


    if (Input.GetKeyDown(KeyCode.A)) //_______________________________________MOVING LEFT
    {
        rigid.velocity = new Vector2(-1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.A))
    {
        rigid.velocity = new Vector2(0, rigid.velocity.y);
    }

    if (Input.GetKeyDown(KeyCode.D)) //_______________________________________MOVING RIGHT
    {
        rigid.velocity = new Vector2(1 * Speed, rigid.velocity.y);
    }
    else if (Input.GetKeyUp(KeyCode.D))
    {
        rigid.velocity = new Vector2(0, rigid.velocity.y);
    }
}

希望对你有帮助。