SQL Server 上周从太阳到星期六答案

【问题标题】：SQL Server Last week from sun to satSQL Server 上周从太阳到星期六
【发布时间】：2018-09-25 04:06:48
【问题描述】：

我正在尝试从 Sun 获取日期到上周的星期六，我的代码是，

Declare
      @now DateTime, @fmWeek DateTime, @toWeek DateTime

Set @now = GetDate()
Set @fmWeek = Convert(DateTime, DateAdd(wk, DateDiff(wk, 0, @now), -1))
Set @toWeek = DATEADD(ms,-3,Convert(DateTime, DateAdd(wk, DateDiff(wk, 0,  @now), 6)))

select @fmWeek, @toWeek

它显示了从2018-04-15 00:00:00.000 到2018-04-21 23:59:59.997 的数据

我需要获取前一周太阳的日期，而不是同一周

【问题讨论】：

标签： sql sql-server tsql datetime sql-server-2014

【解决方案1】：

我需要获取前一周太阳的日期，而不是同一周

我会减去 7 天：

Declare @now DateTime = GetDate()
    ,@fmWeek DateTime, @toWeek DateTime;

Set @fmWeek = DateAdd(wk, DateDiff(wk, 0, @now), -1) - 7;
Set @toWeek = DateAdd(wk, DateDiff(wk, 0, @now), 5) - 7;
select @fmWeek, @toWeek;

DBFiddle Demo

【讨论】：

【解决方案2】：

如果您只想显示两个日期，@lad2025 为您提供了正确的查询来获取日期。

如果你想显示这两天之前的所有日期，你可以尝试如下。

Declare @now DateTime = GetDate()
    ,@fmWeek DateTime, @toWeek DateTime;

Set @fmWeek = DateAdd(wk, DateDiff(wk, 0, @now), -1) - 7;
Set @toWeek = DateAdd(wk, DateDiff(wk, 0, @now), 5) - 7;

SELECT @fmWeek + RN AS DATE FROM
(   
    SELECT (ROW_NUMBER() OVER (ORDER BY (SELECT NULL)))-1 RN 
    FROM   master..[spt_values] T1
) T 
WHERE RN <= DATEDIFF(DAY,@fmWeek,@toWeek)

输出：

Date
------------------------
2018-04-08 00:00:00.000
2018-04-09 00:00:00.000
2018-04-10 00:00:00.000
2018-04-11 00:00:00.000
2018-04-12 00:00:00.000
2018-04-13 00:00:00.000
2018-04-14 00:00:00.000

【讨论】：