clang：错误：链接器命令失败，退出代码为 1（使用 -v 查看调用）Titanium答案

【问题标题】：clang: error: linker command failed with exit code 1 (use -v to see invocation) Titaniumclang：错误：链接器命令失败，退出代码为 1（使用 -v 查看调用）Titanium
【发布时间】：2013-05-15 01:56:18
【问题描述】：

加载 Titanium 模块时出现以下错误：

clang: error: linker command failed with exit code 1 (use -v to see invocation) [ERROR] 
[ERROR] Error: Traceback (most recent call last):
  File "/Users/goodlogics/Library/Application Support/Titanium/mobilesdk/osx/3.1.0.GA/iphone/builder.py", line 1379, in main
    execute_xcode("iphonesimulator%s" % link_version,["GCC_PREPROCESSOR_DEFINITIONS=__LOG__ID__=%s DEPLOYTYPE=development TI_DEVELOPMENT=1 DEBUG=1 TI_VERSION=%s %s %s" % (log_id,sdk_version,debugstr,kroll_coverage)],False)
  File "/Users/goodlogics/Library/Application Support/Titanium/mobilesdk/osx/3.1.0.GA/iphone/builder.py", line 1286, in execute_xcode
    output = run.run(args,False,False,o)
  File "/Users/goodlogics/Library/Application Support/Titanium/mobilesdk/osx/3.1.0.GA/iphone/run.py", line 41, in run
    sys.exit(rc)
SystemExit: 65

【问题讨论】：

标签： clang linker-errors titanium-modules

【解决方案1】：

您是否按照 IOS 模块指南中有关添加新框架的部分中的说明进行操作？

iOSModuleDevelopmentGuide Adding Special Compiler Directives

【讨论】：