如何找出旋转文本框的坐标答案

【问题标题】：How to find out the coordinates of rotated textframe如何找出旋转文本框的坐标
【发布时间】：2011-02-28 13:27:33
【问题描述】：

借助 (idml) itemtransform 水平/垂直距离和路径点数组，我可以找出文本框的坐标 (x1,y1), (x2,y2), (x3,y3), (x4, y4)。如果旋转文本框，则项目变换值会发生变化，但路径点数组值是相同的。我可以通过矩阵 [cos(θ) sin(θ) -sin(θ) cos(θ) 0 0] 找到旋转角度，但我无法获得旋转文本框的确切坐标。文本框如下所示。

普通文本框

  <TextFrame Self="u136" ParentStory="u124" ItemTransform="1 0 0 1 101.72727272727272 -349.41818181818184">
        <Properties>
            <PathGeometry>
                <GeometryPathType PathOpen="false">
                    <PathPointArray>
                        <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                        <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                        <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                        <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                    </PathPointArray>
                </GeometryPathType>
            </PathGeometry>
        </Properties>

旋转的文本框

 <TextFrame Self="u136" ParentStory="u124" ItemTransform="0 1 -1 0 320.3805483338268 -125.07900895050204">
        <Properties>
            <PathGeometry>
                <GeometryPathType PathOpen="false">
                    <PathPointArray>
                        <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                        <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                        <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                        <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                    </PathPointArray>
                </GeometryPathType>
            </PathGeometry>
        </Properties>

当我将旋转文本框的值转换为坐标并在屏幕上绘制时，我没有得到它在原始文本中绘制的确切位置。

谁能帮我找出旋转文本框的坐标。

提前致谢。

【问题讨论】：

嗨，我怎样才能获得文本框的高度、宽度和 x、y 位置？

标签： text coordinates rotation frame adobe-indesign

【解决方案1】：

TextFrame 的 ItemTransform 属性 (a b c d e f) 中的值表示一个二维空间变换矩阵，用于根据以下矩阵乘法公式从 TextFrame 的内部坐标系转换回父坐标系：

| Xparent |   | a  c  e |   | X |
| Yparent | = | b  d  f | * | Y |
| 1       |   | 0  0  1 |   | 1 |

其中X、Y是TextFrame内部坐标系中的坐标，Xparent和Yparent是父级（Spread等）坐标系中对应的坐标。

欲了解更多信息，请参阅7 Coordinate Systems, Transformations and Units

【讨论】：