【发布时间】:2017-05-06 09:27:17
【问题描述】:
MySQL Workbench 创建了这段代码,而不是我。我只是使用了 GUI。
Operation failed: There was an error while applying the SQL script to the database.
Executing:
ALTER TABLE `isometr1_keyboard`.`records`
ADD CONSTRAINT `fk_records_layout_id`
FOREIGN KEY ()
REFERENCES `isometr1_keyboard`.`layouts` ()
ON DELETE NO ACTION
ON UPDATE NO ACTION;
ERROR 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')
REFERENCES `isometr1_keyboard`.`layouts` ()
ON DELETE NO ACTION
ON UPDAT' at line 3
SQL Statement:
ALTER TABLE `isometr1_keyboard`.`records`
ADD CONSTRAINT `fk_records_layout_id`
FOREIGN KEY ()
REFERENCES `isometr1_keyboard`.`layouts` ()
ON DELETE NO ACTION
ON UPDATE NO ACTION
我不明白错误在哪里。也不明白为什么 GUI 创建的代码有问题。
我做错了吗?
【问题讨论】:
-
嗯,是的。空括号需要一个或多个逗号。
-
没关系。列的数据类型不匹配。我希望错误消息这么说。
-
您没有为外键选择任何源或目标列。
标签: mysql mysql-workbench